If your null and alternative hypothesis are: H0:μ=72 H1:μ≠72 Then the test is: two tailed left tailed right tailed
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If your null and alternative hypothesis are:
H0:μ=72
H1:μ≠72
Then the test is:
- two tailed
- left tailed
- right tailed
Given,
H0:μ=72
H1:μ≠72
Step by step
Solved in 2 steps
- for a two tailed test, if z=2.04, find the p valueSuppose there is a claim that a certain population has a mean, H, that is different than 5. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.10 level of significance. To start this test, you write the null hypothesis, Ho, and the alternative hypothesis, H1, as follows. Hg: u= 5 H1: u=5 Suppose you also know the following information. The value of the test statistic based on the sample is 1.506 (rounded to 3 decimal places). The p-value is 0.132 (rounded to 3 decimal places). (a) Complete the steps below for this hypothesis test. Standard Normal Distribution 04 Step 1: Select one-tailed or two-tailed. O One-tailed O Two-tailed 0.3+ Step 2: Enter the test statistic. (Round to 3 decimal places.) 0.2 Step 3: Shade the area represented by the p-value. 0.1+ Step 4: Enter the p-value. (Round to 3 decimal places.) ? (b) Based on your answer to part (a), which statement below is true? Since the p-value is less…The null and alternate hypotheses are: He: P₁ =H₂ H₁ H₁ #P₂ A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12. A random sample of 17 observations from the second population revealed a sample mean of 342 and a sample standard deviation of 15. The population variances are assumed to be equal. At the 0.10 significance level, is there a difference in the population means? a. Is this a one-tailed or a two-tailed test? O One-tailed test. OTwo-tailed test. b. State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) The decision rule is to reject H0 if t
- Q1: A researcher was interested in the effect of exercise on stress levels. For the general population, the distribution of the Stress Battery Scale scores is normal with the mean of µ = 25 and the standard deviation of σ = 5. A sample of n = 100 participants was asked to exercise for three weeks and then reported their stress levels. The sample mean was ?X = 23. Conduct a hypothesis test and determine the effect of exercise. Use the two-tailed test α = .01 1.Type the null and research hypotheses in complete sentences. 2.Cut off points 3.Standard error and z-score -show your computation process 4.Your conclusion thoroughly.Suppose there is a claim that a certain population has a mean, 4, that is different than 9. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.05 level of significance. To start this test, you write the null hypothesis, Ho, and the alternative hypothesis, H1, as follows. Hg: 4= 9 H: u=9 Suppose you also know the following information. The value of the test statistic based on the sample is -2.044 (rounded to 3 decimal places). The p-value is 0.041 (rounded to 3 decimal places). (a) Complete the steps below for this hypothesis test. Standard Normal Distribution 04 Step 1: Select one-tailed or two-tailed. O One-tailed Two-tailed 0.3+ Step 2: Enter the test statistic. (Round to 3 decimal places.) 0.2+ Step 3: Shade the area represented by the p-value. 0.1+ Step 4: Enter the p-value. (Round to 3 decimal places.) ? (b) Based on your answer to part (a), which statement below is true? O since the p-value is less…The mean height of a certain kind of plant is 170 centimeters. Suppose we want to carry out a hypothesis test to see if the mean height when these plants are treated with a certain chemical differs from 170. State the null hypothesis H0 and the alternative hypothesis H1 that we would use for this test.
- Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?A report states the average temperature for the month of June on a specific tropical island is 98 degrees F. A meteorologist claims the report is not correct.. Data collected from 35 areas on the island showed an average temperature of 94 degrees F. Thepopulation standarddeviation is known to be 6.0 degrees F. At alpha = 0.05, can the report's average be rejected? For multiple choice question #1, tell what type of test: right-tailed, left-tailed, or two-tailed.Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. a. Identify the independent and dependent variables. b. In a sentence, state the null hypothesis being tested. c. Using symbols, state the null and alternative hypotheses. d. Determine the critical region using a one-tailed test with alpha = .05. e .Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). f. State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). g. Based on your analysis, is there a relationship between the drug and attention span?
- The test statistic for a left-tailed test is z=-1.42. Solve for the P-value.A simple random sample of 95 basketball players is taken from different teams and their mean weight is found to be 226 pounds and the standard deviation of the population is 20 pounds. Using 0.05 level of significance, test the claim that the average weight for all basketball players is 231 pounds. Complete the following steps: Step # 1: Write the null hypothesis Ho [ Select ] and the alternative hypothesis H1 [ Select ] and identify the claim [Select] Step # 2: Indicate what type of test has to be used [Select ] and find the critical value(s). ( Select ] Step # 3: Find the test value. [ Select ] Step # 4: Make the decision about the null hypothesis. [ Select ] Step # 5: Summarize the result. (Select JSuppose that we have a problem for which the null and alternative hypothesis are given by: H0: μ = 890. H1:μ ≠ 890. Is this a right-tailed test, left-tailed test, or two-tailed test. Find the z value based on a level of significance of α=.09.