If you wanted to make an accurate scale model of the hydro- gen atom and decided that the nucleus would have a diameter of 1 mm, what would be the diameter of the entire model? I understand the answer however wouldnt the end result be much smaller than 106 mm since we are only find the diameter of the nucleus?Is the 106 always used in these types of equations? What would be used in this equation for say a carbon atom? ### To Determine: The diameter value for an accurate scale model of the hydrogen atom.**Given:**- Diameter of hydrogen nucleus, \( d = 1 \text{ mm} \)**Formula:**- Radius of a hydrogen atom is \( 10^6 \) times higher than the nuclear radius.Hence, the diameter of the entire system is given by:\[ d_e = 10^6 \times d \]Where:- \( d_e \) is the diameter of the entire system.**Substitute the value of \( d \) in the above equation:**\[ d_e = 10^6 \times 1 = 10^6 \text{ mm} \]

No, the end result will not be much smaller than 106 mm. This is because it is an hypothetical model…

Answered: If you wanted to make an accurate scale…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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If you wanted to make an accurate scale model of the hydro- gen atom and decided that the nucleus would have a diameter of 1 mm, what would be the diameter of the entire model?

I understand the answer however wouldnt the end result be much smaller than 10⁶ mm since we are only find the diameter of the nucleus?

Is the 10⁶ always used in these types of equations? What would be used in this equation for say a carbon atom?

### To Determine: The diameter value for an accurate scale model of the hydrogen atom.

**Given:**
- Diameter of hydrogen nucleus, \( d = 1 \text{ mm} \)

**Formula:**
- Radius of a hydrogen atom is \( 10^6 \) times higher than the nuclear radius.

Hence, the diameter of the entire system is given by:
\[ d_e = 10^6 \times d \]

Where:
- \( d_e \) is the diameter of the entire system.

**Substitute the value of \( d \) in the above equation:**
\[ d_e = 10^6 \times 1 = 10^6 \text{ mm} \]

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