if you measure the wavelength and color intensity of LED vs fluorescent vs natural light (ie sunlight), what is the result?
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A: Given data: Color temperature of LED bulb is, T=3499 K.
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A: Given : Four energy levels with energies : n=1 = 0eV n= 2 = 2eV n= 3 = 2.4eV n= 4 = 4.2 eV
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Q: = 5. Consider a dielectric mirror that is made up of quarter wave layers of GaAs with n and AlAs…
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A: Energy of photon : According to Planck, the energy of photon of frequency ν is given by E=hv…
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Q: How much more energy does a 33 nm photon have than a 8670 nm photon? Does the 33 nm photon move at a…
A: The energy of 33nm photon is given by, E1=hcλ1 Here, h is the Planck's constant, c is the speed of…
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Q: If you know that the energy required to remove an electron from a metal surface is 3.54 ev. A…
A: In order to photoelectric take place the minimum energy required is: 3.54 eV Therefore, hν=3.54…
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A: Work function,
if you measure the wavelength and color intensity of LED vs fluorescent vs natural light (ie sunlight), what is the result?
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- How many photons are produced in a laser pulse of 0.291 J at 493 nm?Suppose you measured a spectrum of a laser source which peaks at a wavelength of 810 nm. Find the energy (in eV) associated with this wavelength. From the LED spectrum data you want to find the width of the peak at half the height of the peak. The wavelengths at which the intensity is half of its peak value are 630 nm and 666 nm respectively. Using these wavelengths determine the width of the peak in units of energy (eV). From the N2 spectrum data you noted two prominent peaks at wavelengths 330 nm and 350 nm. Determine the energy associated with each peak. The larger energy represents the energy difference between the vibrational ground states of two molecular orbitals (denoted by C’IIu and B³IIL). The smaller one represents the energy difference between the vibrational ground state of the C'II, orbital and first excited vibrational state of B³II.. The difference between these energies represents the energy difference between the ground and first excited vibrational levels. Find this…Calculate the de Broglie wavelength of an electron moving with 1/3rd of the speed of light in vacuum. (Neglect relativistic effect) (Planck's constant : h = 6.63 × 10-34 Js, Mass of electrons : m = 9.11 × 10-28 g) %3D