If you measure the change in concentration of NOCl(g), how will that relate to the rate of Cl2(g) formation? 2NOCL(g) = 2NO(g) + Cl2(g) A. The Cl2 rate will be half of the NOCl rate. B. The Cl2 rate will be double the NOCl rate. C. The Cl2 rate will be the same as the NOCl rate.
If you measure the change in concentration of NOCl(g), how will that relate to the rate of Cl2(g) formation? 2NOCL(g) = 2NO(g) + Cl2(g) A. The Cl2 rate will be half of the NOCl rate. B. The Cl2 rate will be double the NOCl rate. C. The Cl2 rate will be the same as the NOCl rate.
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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If you measure the change in concentration of NOCl(g), how will that relate to the rate of Cl2(g) formation?
2NOCL(g) = 2NO(g) + Cl2(g)
A. The Cl2 rate will be half of the NOCl rate.
B. The Cl2 rate will be double the NOCl rate.
C. The Cl2 rate will be the same as the NOCl rate.
Expert Solution
Step 1
For the reaction -
2NOCL(g) = 2NO(g) + Cl2(g)
The rate of reaction for different Reactants and Products can be written as -
Rate of reaction = Concentration of reactacts or Products/time interval
Rate of reaction = -(1/2)∆[NOCl]/∆t = +(1/2)∆[NO]/∆t = ∆[Cl2]/∆t
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