If you have the following node declaration: struct Node { int number; struct Node * next; }; typedef struct Node node; node *head,*newNode; Write a C program that contains the following functions to manipulate this linked list : -----function named changeFirstAndLast that swaps the node at the end of the list and the node at the beginning of the list. The function will take a list as a parameter and return the updated list. -----function using given prototype below. This function cuts the first node of the list and adds it to the end as last node. It takes beginning address of the list as a parameter and returns the updated list. node* cutheadaddlast(node* head);
If you have the following node declaration: struct Node { int number; struct Node * next; }; typedef struct Node node; node *head,*newNode; Write a C program that contains the following functions to manipulate this linked list : -----function named changeFirstAndLast that swaps the node at the end of the list and the node at the beginning of the list. The function will take a list as a parameter and return the updated list. -----function using given prototype below. This function cuts the first node of the list and adds it to the end as last node. It takes beginning address of the list as a parameter and returns the updated list. node* cutheadaddlast(node* head);
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter7: Arrays
Section7.5: Case Studies
Problem 3E
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If you have the following node declaration:
struct Node {
int number;
struct Node * next;
};
typedef struct Node node;
node *head,*newNode;
Write a C program that contains the following functions to manipulate this linked list :
-----function named changeFirstAndLast that swaps the node at the end of the list and the node at the beginning of the list. The function will take a list as a parameter and return the updated list.
-----function using given prototype below. This function cuts the first node of the list and adds it to the end as last node. It takes beginning address of the list as a parameter and returns the updated list.
node* cutheadaddlast(node* head);
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