If you dilute 35.0 mL of 2.25 M hydrochloric acid to 550. mL, what is the molar concentration of the dilute acid? Molar concentration = M

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**Chapter 4 - Stoichiometry: Quantitative Information About Chemical Reactions**

**Problem:**

If you dilute 35.0 mL of 2.25 M hydrochloric acid to 550. mL, what is the molar concentration of the dilute acid?

Molar concentration = _______ M

---

**Explanation:**

To solve this dilution problem, use the dilution formula:

\[ C_1V_1 = C_2V_2 \]

Where:
- \( C_1 \) is the initial concentration (2.25 M),
- \( V_1 \) is the initial volume (35.0 mL),
- \( C_2 \) is the final concentration (unknown),
- \( V_2 \) is the final volume (550. mL).

Rearrange the equation to solve for \( C_2 \):

\[ C_2 = \frac{C_1 \times V_1}{V_2} \]

This equation allows calculating the final molar concentration after dilution. Plug the values into the equation to find the answer.
Transcribed Image Text:**Chapter 4 - Stoichiometry: Quantitative Information About Chemical Reactions** **Problem:** If you dilute 35.0 mL of 2.25 M hydrochloric acid to 550. mL, what is the molar concentration of the dilute acid? Molar concentration = _______ M --- **Explanation:** To solve this dilution problem, use the dilution formula: \[ C_1V_1 = C_2V_2 \] Where: - \( C_1 \) is the initial concentration (2.25 M), - \( V_1 \) is the initial volume (35.0 mL), - \( C_2 \) is the final concentration (unknown), - \( V_2 \) is the final volume (550. mL). Rearrange the equation to solve for \( C_2 \): \[ C_2 = \frac{C_1 \times V_1}{V_2} \] This equation allows calculating the final molar concentration after dilution. Plug the values into the equation to find the answer.
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