If you 3.7 grams of BeCl₂ and 20 ml of a 3M solution of LiH and you make 0.22 grams of BeH₂ and .99 grams of LiCl. e. What is your theoretical yield of BeH₂ in grams? f. What is your theoretical yield of LiCl in moles? g. What is your theoretical yield of LiCl in grams? h. What are your percent yields?

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**Chemistry Problem: Reaction Yield Calculations**

Given:
- 3.7 grams of BeCl₂
- 20 ml of a 3M solution of LiH
- Products obtained: 0.22 grams of BeH₂ and 0.99 grams of LiCl

**Questions:**

e. What is your theoretical yield of BeH₂ in grams?

f. What is your theoretical yield of LiCl in moles?

g. What is your theoretical yield of LiCl in grams?

h. What are your percent yields?

---

**Explanation and Steps:**

1. **Molar Masses:**
   - BeCl₂ (Beryllium Chloride): Beryllium (Be) = 9.012 g/mol; Chlorine (Cl) = 35.453 g/mol
     \[
     \text{Molar Mass of BeCl₂} = 9.012 + 2 \times 35.453 = 79.918 \, \text{g/mol}
     \]
   - LiH (Lithium Hydride): Lithium (Li) = 6.941 g/mol; Hydrogen (H) = 1.008 g/mol
     \[
     \text{Molar Mass of LiH} = 6.941 + 1.008 = 7.949 \, \text{g/mol}
     \]
   - BeH₂ (Beryllium Hydride): Beryllium (Be) = 9.012 g/mol; Hydrogen (H) = 1.008 g/mol
     \[
     \text{Molar Mass of BeH₂} = 9.012 + 2 \times 1.008 = 11.028 \, \text{g/mol}
     \]
   - LiCl (Lithium Chloride): Lithium (Li) = 6.941 g/mol; Chlorine (Cl) = 35.453 g/mol
     \[
     \text{Molar Mass of LiCl} = 6.941 + 35.453 = 42.394 \, \text{g/mol}
     \]

2. **Balanced Chemical Equation:**
   \[
   \text{BeCl₂} + 2\text{LiH} \rightarrow \text{BeH₂} + 2\text{LiCl}
   \]

3.
Transcribed Image Text:**Chemistry Problem: Reaction Yield Calculations** Given: - 3.7 grams of BeCl₂ - 20 ml of a 3M solution of LiH - Products obtained: 0.22 grams of BeH₂ and 0.99 grams of LiCl **Questions:** e. What is your theoretical yield of BeH₂ in grams? f. What is your theoretical yield of LiCl in moles? g. What is your theoretical yield of LiCl in grams? h. What are your percent yields? --- **Explanation and Steps:** 1. **Molar Masses:** - BeCl₂ (Beryllium Chloride): Beryllium (Be) = 9.012 g/mol; Chlorine (Cl) = 35.453 g/mol \[ \text{Molar Mass of BeCl₂} = 9.012 + 2 \times 35.453 = 79.918 \, \text{g/mol} \] - LiH (Lithium Hydride): Lithium (Li) = 6.941 g/mol; Hydrogen (H) = 1.008 g/mol \[ \text{Molar Mass of LiH} = 6.941 + 1.008 = 7.949 \, \text{g/mol} \] - BeH₂ (Beryllium Hydride): Beryllium (Be) = 9.012 g/mol; Hydrogen (H) = 1.008 g/mol \[ \text{Molar Mass of BeH₂} = 9.012 + 2 \times 1.008 = 11.028 \, \text{g/mol} \] - LiCl (Lithium Chloride): Lithium (Li) = 6.941 g/mol; Chlorine (Cl) = 35.453 g/mol \[ \text{Molar Mass of LiCl} = 6.941 + 35.453 = 42.394 \, \text{g/mol} \] 2. **Balanced Chemical Equation:** \[ \text{BeCl₂} + 2\text{LiH} \rightarrow \text{BeH₂} + 2\text{LiCl} \] 3.
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