If yo is the solution of the equations xy' + 3y = 2x, y(1) = 8, determine the value of yo(2).

Q: The equation y3=3Bxis the general solution of

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Q: e IVP

A: This equation is belonging to the differential variable calculus equation of the initial variable…

Q: In (Z,5, Đ) solve the equation 30XÐ7 = 2 for x.

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Q: Consider the equation (34)x = (3y)s where x and y are unknown. The number of possible solutions is

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Q: The solution of the  equation 2y = 5y - (18/5) is

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Q: y = (1– 2x) ;y" ¡y"

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Q: Find the general solution of x²y" + 10xy + 8y = x² Use the variation of parameters.

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Q: Solve for y in terms of x   xy=x-y x2 +y2= x+y 2x+y=8

A: Given: To solve for y in terms of xxy=x-y x2 +y2= x+y 2x+y=8

Q: solve: y" - 3y" + 2y = e2x 1+ex

A: To solve the given differential equation :     y'''-3y''+2y=e2x1+ex We will use the method of…

Q: Solve: (пу? + 3у?) dy 2.xdx = 0.

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Q: Q: Solve (3xy+ y ) dx+(x +xy) dy = 0

A: 3xy + y2dx + x2+xydy =0 3xy + y2dx =- x2+xydy  dydx=-3xy + y2 x2+xy Put y = vxv + xdvdx =-3x.vx +…

Q: - Solve the equation z = x² + xy² when x = = 0, zz = y³ and when x = 2, z = y.

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Q: Solve for x and y (3x5y = 22x+1 +22x-1 (3y5x = 22x+2_22x-2

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Q: y6) + 25 y" = 0 p(6)

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Q: xux-yuy+y2u=y2x find the general solution

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Q: Eliminate the arbitrary constant. y=Ax² + Bx³ 7xy "-x²y + 15y = 0 A (В) B (C) D x²y-7xy "+ 15y = 0…

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Q: -3y-9(2y+1)=7-5(6-y) solve for y

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Q: Solve for Z. X= (Y-Z) 3

A: Given: X=23Y-Z We have to solve for Z.

Q: Solve x = x + 2y and y = 2x + y with x(0) = 1 and y(0) = 2.

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Q: If  x3 + y3 = 30, x+y =6, then 1/x+1/y = ?

A: We need to find,

Q: y³ (x + 2y) = C²y

A: The solution is given as

Q: Why y was omitted in equation (2)?

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Q: Y= (10x; + x, } (5x, + x}} 15

A: We have to differentiate partially to this equation:

Q: 28) Solve the equation for x: Vx + 5 = v2x - 5

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Q: 3B(i). Write y = 3x²2 + 12x+5 in the form of y= a (x+h)² + k where a, h and k are constants.

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Q: =). Solve the equation zxx = x² + xy² when x = 0, z, = y³ and when x 2, z = y. %3D

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Q: 2. Use undetermined coefficients method to solve 1 yi = 4yı + 2 - 3e", y2 = 9y1 + 6y2 + 10e'.

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Q: Solve for y. x= (3y+5)/(7y-1)

A: To solve for .

Q: Solve for ‘x’ and ‘y’:(a – b) x + (a + b) y = a2 – b2 – 2ab(a + b) (x + y) = a2 + b2

A: Given,

Q: 7.xy + 3r + (x + 12),² ; dy (² + 1³); = 0 dx

A: see 2nd step.