If X~B(n=1000; P=.2) compute the following: SD(X) = 0x is : 8.21 9.45 12.65 16.46

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**Question: Calculating the Standard Deviation for a Binomial Distribution**

Given a binomial distribution \(X \sim B(n=1000, P=0.2)\), compute the standard deviation \(SD(X) = \sigma_X\):

### Options:
- \( \) 8.21
- \( \) 9.45
- \( \) 12.65
- \( \) 16.46

### Detailed Solution:

To find the standard deviation of a binomial distribution, use the formula:

\[ \sigma_X = \sqrt{n \cdot P \cdot (1 - P)} \]

Where:
- \(n\) is the number of trials.
- \(P\) is the probability of success on a single trial.

Given:
- \(n = 1000\)
- \(P = 0.2\)
- \(1 - P = 0.8\)

Substitute the values into the formula:

\[ \sigma_X = \sqrt{1000 \cdot 0.2 \cdot 0.8} \]

Now, calculate:

\[ \sigma_X = \sqrt{1000 \cdot 0.16} \]
\[ \sigma_X = \sqrt{160} \]
\[ \sigma_X \approx 12.65 \]

Thus, the correct answer is:

- \( \) 8.21
- \( \) 9.45
- \(x\) 12.65
- \( \) 16.46
Transcribed Image Text:**Question: Calculating the Standard Deviation for a Binomial Distribution** Given a binomial distribution \(X \sim B(n=1000, P=0.2)\), compute the standard deviation \(SD(X) = \sigma_X\): ### Options: - \( \) 8.21 - \( \) 9.45 - \( \) 12.65 - \( \) 16.46 ### Detailed Solution: To find the standard deviation of a binomial distribution, use the formula: \[ \sigma_X = \sqrt{n \cdot P \cdot (1 - P)} \] Where: - \(n\) is the number of trials. - \(P\) is the probability of success on a single trial. Given: - \(n = 1000\) - \(P = 0.2\) - \(1 - P = 0.8\) Substitute the values into the formula: \[ \sigma_X = \sqrt{1000 \cdot 0.2 \cdot 0.8} \] Now, calculate: \[ \sigma_X = \sqrt{1000 \cdot 0.16} \] \[ \sigma_X = \sqrt{160} \] \[ \sigma_X \approx 12.65 \] Thus, the correct answer is: - \( \) 8.21 - \( \) 9.45 - \(x\) 12.65 - \( \) 16.46
Expert Solution
Step 1

Given Information 

X ~ B(N=1000,p = 0.2)

Standard deviation is given by

Statistics homework question answer, step 1, image 1

So, Option C is correct i.e σx = 12.65

 

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