If we want to evaluate the integral ) * I= 1= x+29 √2+25 we use the trigonometric substitution x = becomes, in terms of 0, dx, I= de The antiderivative in terms of 9 is (do not forget the absolute value) I= and dx= Finally, when we substitute back to the variable x, the antiderivative becomes Use C for the constant of integration. MY NOTES de and therefore the integral +C

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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If we want to evaluate the integral
X+29
1=√ √√2+25
-1
I
dx,
we use the trigonometric substitution x=
becomes, in terms of 8,
de
I=
The antiderivative in terms of 9 is (do not forget the absolute value) I-
and dx =
Finally, when we substitute back to the variable x, the antiderivative becomes
Use C for the constant of integration.
MY NOTES
de and therefore the integral
+C
Transcribed Image Text:If we want to evaluate the integral X+29 1=√ √√2+25 -1 I dx, we use the trigonometric substitution x= becomes, in terms of 8, de I= The antiderivative in terms of 9 is (do not forget the absolute value) I- and dx = Finally, when we substitute back to the variable x, the antiderivative becomes Use C for the constant of integration. MY NOTES de and therefore the integral +C
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