If we use a hash table, there must be a slot/bucket that has at least a keys assigned to it, where a is the load factor of the current hash table. True False A binary search tree of n nodes may have a depth/height as large as 2(n). False True If A[1.n] is sorted, we can find the k th smallest element in A[1...n] in O(1) time. True False
If we use a hash table, there must be a slot/bucket that has at least a keys assigned to it, where a is the load factor of the current hash table. True False A binary search tree of n nodes may have a depth/height as large as 2(n). False True If A[1.n] is sorted, we can find the k th smallest element in A[1...n] in O(1) time. True False
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![If we use a hash table, there must be a slot/bucket that has at least a keys
assigned to it, where a is the load factor of the current hash table.
True
False
A binary search tree of n nodes may have a depth/height as large as 2(n).
False
True
If A[1...n] is sorted, we can find the k th smallest element in A[1..n] in O(1)
time.
True
False](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff92035f2-89dc-43c7-8cbf-4d7ac596d282%2Ff01c0238-3eb8-46f7-8ec1-284c2994d9e1%2Fdni0k6_processed.png&w=3840&q=75)
Transcribed Image Text:If we use a hash table, there must be a slot/bucket that has at least a keys
assigned to it, where a is the load factor of the current hash table.
True
False
A binary search tree of n nodes may have a depth/height as large as 2(n).
False
True
If A[1...n] is sorted, we can find the k th smallest element in A[1..n] in O(1)
time.
True
False
Expert Solution
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Step 1
In hash table, it contains keys and in that keys the values are inserted.
The load factor in the hash table= number of elements/number of slots.
That means load factor defines the average number of elements per slot. So, given statement is True. Because to get the average as , some slots are less than load factor, to balance it definitely some slots contain at least keys.
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