If we take air friction into account, argue that 1/2 (mv^2) + mgy must decrease as a function of time. From this, prove thatthe stone will take longer for the downward motion than for the upward motion.
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Consider a stone thrown vertically upward. If we take air friction into
account, argue that
1/2 (mv^2) + mgy must decrease as a function of time. From this, prove thatthe stone will take longer for the downward motion than for the upward motion.
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