Title: Understanding Memory Addresses in ArraysIf we store the following array of 1-byte values at memory address **0x54**, what is the memory address of the value in **arr[3]**?```plaintextarr = [ 0x10, 0x42, 0x09, 0x23, 0x77, 0x92 ]```Options:- A. 0x23- B. 0x54- C. 0x56- D. 0x57- E. None of the above### Explanation:The given array `arr` starts at memory address `0x54`. Since each value in the array is 1-byte, the value at index `3` would be located at the fourth position:- `arr[0]` is at `0x54`- `arr[1]` is at `0x55`- `arr[2]` is at `0x56`- `arr[3]` is at `0x57`Therefore, the correct memory address of the value in `arr[3]` is `0x57`. The correct answer is option **D**.

Answered: If we store the following array of…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Using C Language In this function, b has the address of a memory buffer that is num_bytes long. The function should repeatedly copy the 16 byte pattern that pattern16 points at into the memory buffer until num_bytes have been written. If num_bytes is not a multple of 16, the final write of the 16 byte pattern should be truncated to finish filling the buffer. void memset16(void *b, int num_bytes, void *pattern16) For example if the 16 bytes that pattern16 points at is 00 11 22 33 44 55 66 77 88 99 aa bb cc dd ee ff, then memset(b, 20, pattern16) should write to the buffer pointed at by p the 20 bytes 00 11 22 33 44 55 66 77 88 99 aa bb cc dd ee ff 00 11 22 33. Use SSE instructions to improve efficiency. Here's pseudocode. x = SSE unaligned load from pattern16while (num_bytes >= 16) SSE unaligned store x to p advance p by 16 bytes decrement num_bytes by 16while (num_bytes > 0) store 1 byte from pattern16 to p advance p by 1 byte advance pattern16 by 1 byte…
The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp); printf("The character at cp is…
a. Given the variables valuesArray and arrayPtr defined below, assign the variable arravPtr to the valuesArray and do pointer arithmetic to print out (using a cout statement) each element of valuesArray. int valuesArray[3] = {66, 23, 92}; int *arrayPtrị b. The address of valuesArrav[0] is Ox7ffc125d3e20. What is the address of these elements of the array? valuesArray[1] address is: valuesArray[2] address is: ww m me

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If we store the following array of 1-byte values at memory address 0x54, what is the memory address of the value in arr[3]? arr = [0x10, 0x42, 0x09, 0x23, 0x77, 0x92 ] A. 0x23 B. 0x54 C. 0x56 D. Ox57 O E. None of the above