If we neglect air resistance, then the range of a ball (or any projectile) shot at an angle θ with respect to the x axis and with an initial velocity v0, is given byR(θ)= (V0^2/g) sin(2θ) for 0 ≤ θ ≤ pie/2 where g is the acceleration due to gravity (9.8 meters per second per second).For what value of θ is the maximum range attained? (Note that the answer is numerical, not symbolic.)
If we neglect air resistance, then the range of a ball (or any projectile) shot at an angle θ with respect to the x axis and with an initial velocity v0, is given byR(θ)= (V0^2/g) sin(2θ) for 0 ≤ θ ≤ pie/2 where g is the acceleration due to gravity (9.8 meters per second per second).For what value of θ is the maximum range attained? (Note that the answer is numerical, not symbolic.)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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If we neglect air resistance, then the range of a ball (or any projectile) shot at an angle θ with respect to the x axis and with an initial velocity v0, is given by
R(θ)= (V0^2/g) sin(2θ) for 0 ≤ θ ≤ pie/2
where g is the acceleration due to gravity (9.8 meters per second per second).
For what value of θ is the maximum range attained? (Note that the answer is numerical, not symbolic.)
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