If we multiply the Legendre polynomial of degree n by an appropriate scalar, we can obtain a polynomial L(x) such that L(1) = 1. (a) Find Lo(x), L₂(x), L₂(x), and L₂(x). 40(x)= 4₂(x)= 4₂(x)= Ly(x) = W
If we multiply the Legendre polynomial of degree n by an appropriate scalar, we can obtain a polynomial L(x) such that L(1) = 1. (a) Find Lo(x), L₂(x), L₂(x), and L₂(x). 40(x)= 4₂(x)= 4₂(x)= Ly(x) = W
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Subject: calculus

Transcribed Image Text:If we multiply the Legendre polynomial of degree n by an appropriate scalar, we can obtain a polynomial L,(x) such that L,(1) = 1.
(a) Find Lo(x), L₂(x), L₂(x), and L₂(x).
Lo(x)=
4₂(x)=
Ly(x) =
(b) It can be shown that L,(x) satisfies the recurrence relation
Ln(x) = 2n-1x₂-1(x)=Ln-2(x)
n
for all n 2 2. Verify this recurrence for L₂(x) and L3(x). Then use it to compute L4(x) and Lg(x).
L5(x)
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