If we assume that the above proportion is still true in 2021, how likely is it to find a random sample of n exceeding 11% ? 125 individuals that results in a sample proportion %3D

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The prevalence of cannabis use among Canadians 15 years of age and older was 9.1% in
2011(according to Statistics Canada).
уears
If we were to sample n = 125 individuals, what would be the approximate
The mean is calculated as:
distribution of the sample proportion îp ? give the mean, the standard deviation and
the name of the approximate distribution of such sample proportion as well as the
name of the theorem used to justify your claims
H=n•p=125 - 0.091 = 11.375
%3D
The variance is calculated as:
o² = n·p· (1 – p) = 125 - 0.091 · 0.909 = 10.3399
%3|
The standard deviation is calculated as:
= yn•p·(1 – p)
= V10.3399 = 3.2156
%3D
If we assume that the above proportion is still true in 2021, how likely is it
to find a random sample of n =
125 individuals that results in a sample proportion
exceeding 11% ?
Transcribed Image Text:The prevalence of cannabis use among Canadians 15 years of age and older was 9.1% in 2011(according to Statistics Canada). уears If we were to sample n = 125 individuals, what would be the approximate The mean is calculated as: distribution of the sample proportion îp ? give the mean, the standard deviation and the name of the approximate distribution of such sample proportion as well as the name of the theorem used to justify your claims H=n•p=125 - 0.091 = 11.375 %3D The variance is calculated as: o² = n·p· (1 – p) = 125 - 0.091 · 0.909 = 10.3399 %3| The standard deviation is calculated as: = yn•p·(1 – p) = V10.3399 = 3.2156 %3D If we assume that the above proportion is still true in 2021, how likely is it to find a random sample of n = 125 individuals that results in a sample proportion exceeding 11% ?
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