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If u(x, t) = D1 fn(t) sin(nx) is the solution Utt – 9ura = 2e2t sin(3x) + e-2t sin(4x) u(0, t) = 0 = u(T, t) u(x,0) = sin(3x) u (x,0) = –2 sin(4x). Then the coditions for y = f4(t) are

If u(x, t) = D1 fn(t) sin(nx) is the solution Utt – 9ura = 2e2t sin(3x) + e-2t sin(4x) u(0, t) = 0 = u(T, t) u(x,0) = sin(3x) u (x,0) = –2 sin(4x). Then the coditions for y = f4(t) are

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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If u(x, t) = D=1 fn(t) sin(nx) is the solution Utt – 9upa = 2e²t sin(3x) +e-2t sin(4x) u(0, t) = 0 = u(T, t) u(x, 0) = sin(3x) u (x, 0) = -2 sin(4x). Then the conditions for y = f4(t) are
Transcribed Image Text:If u(x, t) = D=1 fn(t) sin(nx) is the solution Utt – 9upa = 2e²t sin(3x) +e-2t sin(4x) u(0, t) = 0 = u(T, t) u(x, 0) = sin(3x) u (x, 0) = -2 sin(4x). Then the conditions for y = f4(t) are
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