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If u and v are the vectors below, solve the following equation for the vector x. 4 3 u= 4 -1 -3v-u-2x = v-2(2x+2u) 0 X= 0 V = 2

If u and v are the vectors below, solve the following equation for the vector x. 4 3 u= 4 -1 -3v-u-2x = v-2(2x+2u) 0 X= 0 V = 2

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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If **u** and **v** are the vectors below, solve the following equation for the vector **x**. \[ \mathbf{u} = \begin{bmatrix} 4 \\ 4 \\ -1 \\ \end{bmatrix} \quad \mathbf{v} = \begin{bmatrix} 3 \\ -4 \\ 2 \\ \end{bmatrix} \] \[ -3\mathbf{v} - \mathbf{u} - 2\mathbf{x} = \mathbf{v} - 2(2\mathbf{x} + 2\mathbf{u}) \] \[ \mathbf{x} = \begin{bmatrix} 0 \\ 0 \\ 0 \\ \end{bmatrix} \]
Transcribed Image Text:If **u** and **v** are the vectors below, solve the following equation for the vector **x**. \[ \mathbf{u} = \begin{bmatrix} 4 \\ 4 \\ -1 \\ \end{bmatrix} \quad \mathbf{v} = \begin{bmatrix} 3 \\ -4 \\ 2 \\ \end{bmatrix} \] \[ -3\mathbf{v} - \mathbf{u} - 2\mathbf{x} = \mathbf{v} - 2(2\mathbf{x} + 2\mathbf{u}) \] \[ \mathbf{x} = \begin{bmatrix} 0 \\ 0 \\ 0 \\ \end{bmatrix} \]
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