If two parallel lines are cut by a transversal, then the pairs of altermate interior angles have the same measure. 4/3 Given: p || 4 Prove: m23 = m25 Complete the proof by writing the missing reasons. Choose from the following reasons. You may use a reason more than once. Same-Side Interior Angles Postulate Given Definition of supplementary angles. Subtraction Property of Equality Substitution Property of Equality Linear Pair Theorem Statements Reasons 1. pg 1. Coen. 3. m23 + m = 180° 3. 6. m25 + m = 180° %3D 7. 7. m23 + m m5+ m %3D 8. 8. m23 = m5 %3D 6.

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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Name:
1.6: Intro to Unknown Angles Proofs
ame:
"Take Cha
1.7 - Proof of Known Facts
If two parallel lines are cut by a transversal, then the
pairs of alternate interior angles have the same measure.
P
Given: p || 4
8.
Prove: m23 = m25
Complete the proof by writing the missing reasons. Choose from the following reasons.
You may use a reason more than once.
Same-Side Interior Angles Postulate
Given
Definition of supplementary angles
Subtraction Property of Equality
Substitution Property of Equality
Linear Pair Theorem
Statements
Reasons
1. pg
1. Coen
3. m23 + m2= 180°
3.
6.
6. m25 + m 180°
7.
7. m23 + m =m25+ m26
8.
8. m23 = m5
Transcribed Image Text:Name: 1.6: Intro to Unknown Angles Proofs ame: "Take Cha 1.7 - Proof of Known Facts If two parallel lines are cut by a transversal, then the pairs of alternate interior angles have the same measure. P Given: p || 4 8. Prove: m23 = m25 Complete the proof by writing the missing reasons. Choose from the following reasons. You may use a reason more than once. Same-Side Interior Angles Postulate Given Definition of supplementary angles Subtraction Property of Equality Substitution Property of Equality Linear Pair Theorem Statements Reasons 1. pg 1. Coen 3. m23 + m2= 180° 3. 6. 6. m25 + m 180° 7. 7. m23 + m =m25+ m26 8. 8. m23 = m5
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