If the vibrational frequency of 1802 is 1764 cm-1, what is the spring constant a.1560 N/m b.1620 N/m c.1640 N/m d.1660 N/m C. X10 K =5.242 x10 f = 5.292x 10
If the vibrational frequency of 1802 is 1764 cm-1, what is the spring constant a.1560 N/m b.1620 N/m c.1640 N/m d.1660 N/m C. X10 K =5.242 x10 f = 5.292x 10
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter18: Raman Spectroscopy
Section: Chapter Questions
Problem 18.5QAP
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![6. If the vibrational frequency of 1802 is 1764 cm-1, what is the spring constant
a.1560 N/m
b.1620 N/m
X10
K = (5.242 x10) (4a2
c.1640 N/m
d.1660 N/m
f = 5.292x 10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F93924627-20b5-4e20-a7be-69a54767599c%2Feb247180-f0d0-4b44-8337-06b257ef6a03%2Fun3p1o8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. If the vibrational frequency of 1802 is 1764 cm-1, what is the spring constant
a.1560 N/m
b.1620 N/m
X10
K = (5.242 x10) (4a2
c.1640 N/m
d.1660 N/m
f = 5.292x 10
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