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If the velocity of the solar wind is about 4.0 x 102 km/s and the visible tail of a comet is 9.0 x 10° km long, how many days does an atom in the solar wind take to travel from the nucleus to the end of the visible tail? (Note: 1 day = 86,400 seconds.) days

If the velocity of the solar wind is about 4.0 x 102 km/s and the visible tail of a comet is 9.0 x 10° km long, how many days does an atom in the solar wind take to travel from the nucleus to the end of the visible tail? (Note: 1 day = 86,400 seconds.) days

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There is one part to this question. I need to know the days. Thank you!

If the velocity of the solar wind is about \(4.0 \times 10^2\) km/s and the visible tail of a comet is \(9.0 \times 10^8\) km long, how many days does an atom in the solar wind take to travel from the nucleus to the end of the visible tail? (Note: 1 day = 86,400 seconds.) [Text box for answer] days
Transcribed Image Text:If the velocity of the solar wind is about \(4.0 \times 10^2\) km/s and the visible tail of a comet is \(9.0 \times 10^8\) km long, how many days does an atom in the solar wind take to travel from the nucleus to the end of the visible tail? (Note: 1 day = 86,400 seconds.) [Text box for answer] days
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The velocity of the solar wind V = 4.0 × 102 km/s

The visible tail of the comet is d = 9.0 × 108 km

 

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