If the values of the joint pdf of X and Y are shown in the table below: 3 X\Y 0 1/12 1/4 1 1/8 1/120 *** 1 1/6 1/4 1/20 *** *** 2 1/24 1/40 Find: a) P(X =1,Y = 2) b) P(X =0,1Y) e) F(2,1)

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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If the values of the joint pdf of X and Y are shown in the table below:

\[
\begin{array}{c|cccc}
XY & 0 & 1 & 2 & 3 \\
\hline
0 & 1/12 & 1/4 & 1/8 & 1/12 & 1/120 \\
1 & 1/6 & 1/4 & 1/20 & *** \\
2 & 1/24 & 1/40 & *** & *** \\
\end{array}
\]

Find:
a) \( P(X = 1, Y = 2) \)

b) \( P(X = 0, 1 \leq Y \leq 3) \)

c) \( P(X + Y \leq 1) \)

d) \( P(X > Y) \)

e) \( F(2,1) \)

**Explanation of the Table:**

This table provides specific probabilities assigned to pairs of random variables X and Y. Each cell in the table corresponds to a joint probability value \( P(X = x, Y = y) \) for the discrete values of X and Y indicated. The asterisks (***) indicate values that are not provided in the table. 

The tasks involve calculating probabilities and cumulative distribution functions using these given probability values.
Transcribed Image Text:If the values of the joint pdf of X and Y are shown in the table below: \[ \begin{array}{c|cccc} XY & 0 & 1 & 2 & 3 \\ \hline 0 & 1/12 & 1/4 & 1/8 & 1/12 & 1/120 \\ 1 & 1/6 & 1/4 & 1/20 & *** \\ 2 & 1/24 & 1/40 & *** & *** \\ \end{array} \] Find: a) \( P(X = 1, Y = 2) \) b) \( P(X = 0, 1 \leq Y \leq 3) \) c) \( P(X + Y \leq 1) \) d) \( P(X > Y) \) e) \( F(2,1) \) **Explanation of the Table:** This table provides specific probabilities assigned to pairs of random variables X and Y. Each cell in the table corresponds to a joint probability value \( P(X = x, Y = y) \) for the discrete values of X and Y indicated. The asterisks (***) indicate values that are not provided in the table. The tasks involve calculating probabilities and cumulative distribution functions using these given probability values.
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