**Problem Statement:**If the total resistance of the circuit is 136 ohms, determine the value of \( R_1 \), given:- \( R_T = 136 \, \Omega \)- \( R_2 = 34 \, \Omega \)- \( R_3 = 20 \, \Omega \)- \( R_4 = 14 \, \Omega \)**Circuit Diagram Explanation:**The circuit consists of a simple series setup with a total of four resistors and a power source. The resistors are labeled as \( R_1 \), \( R_2 \), \( R_3 \), and \( R_4 \). The power source is labeled as \( E_T \).- **Resistors:** - \( R_1 \) is the resistor whose resistance value needs to be determined. It is connected directly to the power source in series with the other resistors. - \( R_2 = 34 \, \Omega \) - \( R_3 = 20 \, \Omega \) - \( R_4 = 14 \, \Omega \)- **Power Source:** - Indicated by the symbol \( E_T \), placed on the left side of the circuit diagram, with positive and negative terminals marked.**Calculating \( R_1 \):**In a series circuit, the total resistance \( R_T \) is the sum of all individual resistances:\[ R_T = R_1 + R_2 + R_3 + R_4 \]Given:\[ R_T = 136 \, \Omega \]Substitute the known values:\[ 136 \, \Omega = R_1 + 34 \, \Omega + 20 \, \Omega + 14 \, \Omega \]Solving for \( R_1 \):\[ R_1 = 136 \, \Omega - (34 \, \Omega + 20 \, \Omega + 14 \, \Omega) \]\[ R_1 = 136 \, \Omega - 68 \, \Omega \]\[ R_1 = 68 \, \Omega \]Hence, the resistance of \( R_1 \) is 68 ohms.

Answered: If the total resistance of the circuit…

If the total resistance of the circuit is 136 ohms, determine the value of R₁, given: R₁ . = 136 Q, R₂ = 34 Q, R₂ = 20 Q, and R₁ = 140 = 2 E₁ R₁ R₂ R₂ R₂ M www

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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