Determine the forces exerted at C and E on the tong BCE.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question

Transcribed Image Text:**Problem 6.141**
A steel ingot weighing 8000 lb is lifted by a pair of tongs as shown. Determine the forces exerted at C and E on the tong BCE.
---
This exercise involves analyzing the forces acting on a mechanical lifting device. A pair of tongs is used to lift a steel ingot weighing 8000 pounds. The objective is to calculate the specific forces exerted at specific points, labeled C and E, on the tong BCE. This type of problem typically involves understanding concepts of static equilibrium, force decomposition, and moments.
**Understanding the Problem:**
- **Weight of Ingot:** 8000 lb
- **Points of Interest:** C and E on the tong BCE
**Approach:**
1. **Free Body Diagram (FBD):**
- Draw an FBD representing the tong as a rigid body.
- Identify all acting forces, including the weight of the ingot and reaction forces at the points C and E.
2. **Equilibrium Equations:**
- Apply the conditions for static equilibrium: sum of forces in all directions should equal zero, and the sum of moments about any point should also equal zero.
- Use these equations to solve for the unknown forces at C and E.
**Applications:**
This problem is practical for understanding real-world applications like material handling in manufacturing, construction, or logistics, where understanding the proper application of forces ensures safety and efficacy in operations.

Transcribed Image Text:The diagram illustrates a mechanical lifting system supporting an 8000 lb weight, suspended by a series of bars and joints.
- The system consists of a pair of crossed links: \( A \) to \( C \) and \( B \) to \( D \), with arrows at the top indicating points \( A \) and \( B \) with upward forces.
- The distance between points \( A \) and \( B \) is 14 inches.
- The horizontal span from point \( C \) to \( D \) is 45 inches.
- Vertical distances are indicated: from \( A \) to \( C \) and \( B \) to \( D \) is 35 inches, and from \( C \) (or \( D \)) to the base points \( E \) and \( F \) is 55 inches.
- The weight is directly attached at the bottom between points \( E \) and \( F \), which are 55 inches apart horizontally.
- The complete assembly shows a mechanical structure that likely operates in a symmetrical manner to balance and lift the central load.
This diagram (Fig. P6.141) aids in understanding the geometric and force relationships within the lift mechanism.
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Follow-up Question

Transcribed Image Text:6.142 If the toggle shown is added to the tongs of Prob. 6.141 and the load is
lifted by applying a single force at G, determine the forces exerted at
C and E on the tong BCE.

Transcribed Image Text:A
8000 lb
G
-73 in.-
Fig. P6.142
B
20 in.
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