If the temperature of the surroundings is -229.32 °C, calculate the entropy change (in J/K) for the system (AS sys), surroundings (ASsur) and universe (AS universe) when 47.4 g of liquid propene (C3H6) freezes.Report your answers to two decimal places.Tfus(°C)-185.25Tvap(°C)-47.69AH°fus (kJ/mol) 3.00AHO vap, (kJ/mol) 18.421. AS sysSubmit Answer2. AS surSubmit Answer3. AS universeSubmit AnswerTries 0/5Tries 0/5Tries 0/5

Given,Temperature of the surroundings=Mass of propene=To find the change in entropy of system,…

If the temperature of the surroundings is -229.32 °C, calculate the entropy change (in J/k) for the system (AS sys), surrou hndings (ASsur) and universe (Suniverse) Report your answers to two decimal places. Trus (°C) Tvap(°C) AH°fus (kJ/mol) 3.00 AHvap (KJ/mol) 18.42 1. AS sys Submit Answer 2. AS sur Submit Answer -185.25 -47.69 Tries 0/5 Tries 0/5 3. AS universe Submit Answer Tries 0/5

If the temperature of the surroundings is -229.32 °C, calculate the entropy change (in J/k) for the system (AS sys), surrou hndings (ASsur) and universe (Suniverse) Report your answers to two decimal places. Trus (°C) Tvap(°C) AH°fus (kJ/mol) 3.00 AHvap (KJ/mol) 18.42 1. AS sys Submit Answer 2. AS sur Submit Answer -185.25 -47.69 Tries 0/5 Tries 0/5 3. AS universe Submit Answer Tries 0/5

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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