If the stone were thrown harder, and left with 1.5 times the initial speed, you might expect it to go farther, but how exactly does that happen? (d) Throwing the stone horizontally at 1.5 times the previous speed multiplies the time to reach the ground by what factor? (e) The horizontal component of the velocity is multiplied by what factor? (f) How many times farther does the stone land from the building?
A stone is thrown from the top of a building upward at an angle of 26.0° to the horizontal with an initial speed of 19.1 m/s as shown in the figure. The height of the building is 45.0 m.
The following questions present a twist on the scenario above to test your understanding.
Suppose another stone is thrown horizontally from the same building. If it strikes the ground 65 m away, find the following values.
FOUND:
a. Time of flight = 3.03 s
b. Initial speed = 21.45 m/s
c. Speed & angle with respect to the horizontal of the velocity vector at impact:
36.62 m/s
54.15°
If the stone were thrown harder, and left with 1.5 times the initial speed, you might expect it to go further, but how exactly does that happen?
d. Throwing the stone horizontally at 1.5 times the previous speed multiplies the time to reach the ground by what factor?
________
e. The horizontal component of the velocity is multiplied by what factor?
________
f. How many times farther does the stone land from the building?
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