If the standard deviation is 8 thousand miles, the proportion of trucks that can be expected to travel between 66 and 80 thousand miles in a year is (Round to four decimal places as needed.) %. If the standard deviation is 8 thousand miles, the percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is (Round to two decimal places as needed.) miles. If the standard deviation is 8 thousand miles, the number of miles that will be traveled by at least 85% of the trucks is (Round to the nearest mile as needed.) Help me solve this View an example Get more help. BI 83°F D # Type here to search-

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A trucking company determined that the distance traveled per truck per year is normally distributed, with a mean of 80 thousand miles and a standard deviation of 10 thousand miles. Compa
below.
(...)
The percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is 8.96 %.
(Round to two decimal places as needed.).
c. How many miles will be traveled by at least 85% of the trucks?
The number of miles that will be traveled by at least 85% of the trucks is 69636 miles.
(Round to the nearest mile as needed.)
d. What are your answers to parts (a) through (c) if the standard deviation is 8 thousand miles?
If the standard deviation is 8 thousand miles, the proportion of trucks that can be expected to travel between 66 and 80 thousand miles in a year is
(Round to four decimal places as needed.)
If the standard deviation is 8 thousand miles, the percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is %.
(Round to two decimal places as needed.)
miles.
If the standard deviation is 8 thousand miles, the number of miles that will be traveled by at least 85% of the trucks is
(Round to the nearest mile as needed.)
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Transcribed Image Text:A trucking company determined that the distance traveled per truck per year is normally distributed, with a mean of 80 thousand miles and a standard deviation of 10 thousand miles. Compa below. (...) The percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is 8.96 %. (Round to two decimal places as needed.). c. How many miles will be traveled by at least 85% of the trucks? The number of miles that will be traveled by at least 85% of the trucks is 69636 miles. (Round to the nearest mile as needed.) d. What are your answers to parts (a) through (c) if the standard deviation is 8 thousand miles? If the standard deviation is 8 thousand miles, the proportion of trucks that can be expected to travel between 66 and 80 thousand miles in a year is (Round to four decimal places as needed.) If the standard deviation is 8 thousand miles, the percentage of trucks that can be expected to travel either less than 60 or more than 95 thousand miles in a year is %. (Round to two decimal places as needed.) miles. If the standard deviation is 8 thousand miles, the number of miles that will be traveled by at least 85% of the trucks is (Round to the nearest mile as needed.) Help me solve this View an example Get more help. 83°F Jess Type here to search &
Given a normal distribution with μ = 100 and o= 10, complete parts (a) through (d).
Click here to view page 1 of the cumulative standardized normal distribution table.
Click here to view page 2 of the cumulative standardized normal distribution table.
...
(Round to four decimal places as needed.)
b. What is the probability that X < 75?
The probability that X <75 is 0.0062.
(Round to four decimal places as needed.)
c. What is the probability that X<95 or X > 105?
The probability that X < 95 or X> 105 is 0.6170
(Round to four decimal places as needed.)
d. 99% of the values are between what two X-values (symmetrically distributed around the mean)?
99% of the values are greater than and less than
(Round to two decima' ces as needed.)
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Transcribed Image Text:Given a normal distribution with μ = 100 and o= 10, complete parts (a) through (d). Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table. ... (Round to four decimal places as needed.) b. What is the probability that X < 75? The probability that X <75 is 0.0062. (Round to four decimal places as needed.) c. What is the probability that X<95 or X > 105? The probability that X < 95 or X> 105 is 0.6170 (Round to four decimal places as needed.) d. 99% of the values are between what two X-values (symmetrically distributed around the mean)? 99% of the values are greater than and less than (Round to two decima' ces as needed.) View instructor tip Help me solve this Get more help - Type here to search
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