If the resultant force acting on a 2.0-kg object is equal to (3i +4j) N. what is the change in kinetic energy as the object moves from (7î - 8) m to (117 -s) m? (A +36J B) +28) +32) D +24J (E) +60J

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A: mass = m = 500 g = 0.5 kg initial speed = Vi= 90 cm/s = 0.9 m/s frictional force = f =0.8 N

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A: Hey dear have a look

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