If the rate of formation of chlorine trifluoride (CIF3) is 0.520 M/s, what is the rate of disappearance of F2? Cl2(g) + 3 F2(g) → 2 CIF3(g) O A. –1.56 M/s B. -0.0433 M/s C.-0.780 M/s O D.-0.173 M/s O E. -0.390 M/s

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### Reaction Rate Question

#### Problem Statement:
If the rate of formation of chlorine trifluoride (ClF₃) is 0.520 M/s, what is the rate of disappearance of F₂?

#### Given Reaction:
\[ \text{Cl}_2(g) + 3 \text{F}_2(g) \rightarrow 2 \text{ClF}_3(g) \]

#### Options:
- A. –1.56 M/s
- B. –0.0433 M/s
- C. –0.780 M/s
- D. –0.173 M/s
- E. –0.390 M/s

#### Explanation:
In this problem, we are asked to determine the rate at which fluorine gas (F₂) is consumed based on the given rate of formation of chlorine trifluoride (ClF₃).

To solve this, we use the stoichiometry of the given reaction. The stoichiometric coefficients indicate the following relationships:
- 2 moles of ClF₃ are formed per 3 moles of F₂ consumed.

Therefore, we can set up a relationship between the rates of formation and disappearance as follows:
\[ \frac{\Delta [\text{ClF}_3]}{\Delta t} \times \frac{3}{2} = -\frac{\Delta [\text{F}_2]}{\Delta t} \]

Given:
\[ \frac{\Delta [\text{ClF}_3]}{\Delta t} = 0.520 \text{ M/s} \]

Thus:
\[ 0.520 \text{ M/s} \times \frac{3}{2} = \frac{\Delta [\text{F}_2]}{\Delta t} \]
\[ 0.520 \times 1.5 = \frac{\Delta [\text{F}_2]}{\Delta t} \]
\[ \frac{\Delta [\text{F}_2]}{\Delta t} = 0.780 \text{ M/s} \]

Since the rate of disappearance is being asked for, which should be given as a negative rate of change:
\[ \frac{\Delta [\text{F}_2]}{\Delta t} = -0.780 \text{ M/s} \]

#### Correct Answer:
C. –0.780 M/s

This calculation confirms that the rate of disappearance of F₂
Transcribed Image Text:### Reaction Rate Question #### Problem Statement: If the rate of formation of chlorine trifluoride (ClF₃) is 0.520 M/s, what is the rate of disappearance of F₂? #### Given Reaction: \[ \text{Cl}_2(g) + 3 \text{F}_2(g) \rightarrow 2 \text{ClF}_3(g) \] #### Options: - A. –1.56 M/s - B. –0.0433 M/s - C. –0.780 M/s - D. –0.173 M/s - E. –0.390 M/s #### Explanation: In this problem, we are asked to determine the rate at which fluorine gas (F₂) is consumed based on the given rate of formation of chlorine trifluoride (ClF₃). To solve this, we use the stoichiometry of the given reaction. The stoichiometric coefficients indicate the following relationships: - 2 moles of ClF₃ are formed per 3 moles of F₂ consumed. Therefore, we can set up a relationship between the rates of formation and disappearance as follows: \[ \frac{\Delta [\text{ClF}_3]}{\Delta t} \times \frac{3}{2} = -\frac{\Delta [\text{F}_2]}{\Delta t} \] Given: \[ \frac{\Delta [\text{ClF}_3]}{\Delta t} = 0.520 \text{ M/s} \] Thus: \[ 0.520 \text{ M/s} \times \frac{3}{2} = \frac{\Delta [\text{F}_2]}{\Delta t} \] \[ 0.520 \times 1.5 = \frac{\Delta [\text{F}_2]}{\Delta t} \] \[ \frac{\Delta [\text{F}_2]}{\Delta t} = 0.780 \text{ M/s} \] Since the rate of disappearance is being asked for, which should be given as a negative rate of change: \[ \frac{\Delta [\text{F}_2]}{\Delta t} = -0.780 \text{ M/s} \] #### Correct Answer: C. –0.780 M/s This calculation confirms that the rate of disappearance of F₂
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