If the rate of formation of chlorine trifluoride (CIF3) is 0.520 M/s, what is the rate of disappearance of F2? Cl2(g) + 3 F2(g) → 2 CIF3(g) O A. –1.56 M/s B. -0.0433 M/s C.-0.780 M/s O D.-0.173 M/s O E. -0.390 M/s
If the rate of formation of chlorine trifluoride (CIF3) is 0.520 M/s, what is the rate of disappearance of F2? Cl2(g) + 3 F2(g) → 2 CIF3(g) O A. –1.56 M/s B. -0.0433 M/s C.-0.780 M/s O D.-0.173 M/s O E. -0.390 M/s
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Reaction Rate Question
#### Problem Statement:
If the rate of formation of chlorine trifluoride (ClF₃) is 0.520 M/s, what is the rate of disappearance of F₂?
#### Given Reaction:
\[ \text{Cl}_2(g) + 3 \text{F}_2(g) \rightarrow 2 \text{ClF}_3(g) \]
#### Options:
- A. –1.56 M/s
- B. –0.0433 M/s
- C. –0.780 M/s
- D. –0.173 M/s
- E. –0.390 M/s
#### Explanation:
In this problem, we are asked to determine the rate at which fluorine gas (F₂) is consumed based on the given rate of formation of chlorine trifluoride (ClF₃).
To solve this, we use the stoichiometry of the given reaction. The stoichiometric coefficients indicate the following relationships:
- 2 moles of ClF₃ are formed per 3 moles of F₂ consumed.
Therefore, we can set up a relationship between the rates of formation and disappearance as follows:
\[ \frac{\Delta [\text{ClF}_3]}{\Delta t} \times \frac{3}{2} = -\frac{\Delta [\text{F}_2]}{\Delta t} \]
Given:
\[ \frac{\Delta [\text{ClF}_3]}{\Delta t} = 0.520 \text{ M/s} \]
Thus:
\[ 0.520 \text{ M/s} \times \frac{3}{2} = \frac{\Delta [\text{F}_2]}{\Delta t} \]
\[ 0.520 \times 1.5 = \frac{\Delta [\text{F}_2]}{\Delta t} \]
\[ \frac{\Delta [\text{F}_2]}{\Delta t} = 0.780 \text{ M/s} \]
Since the rate of disappearance is being asked for, which should be given as a negative rate of change:
\[ \frac{\Delta [\text{F}_2]}{\Delta t} = -0.780 \text{ M/s} \]
#### Correct Answer:
C. –0.780 M/s
This calculation confirms that the rate of disappearance of F₂](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e1de3ec-8a8e-446d-a1ad-fbe652f4aa52%2F8e3bc499-1cd5-41ad-bfa0-559ca6793940%2Fdkwr79j.png&w=3840&q=75)
Transcribed Image Text:### Reaction Rate Question
#### Problem Statement:
If the rate of formation of chlorine trifluoride (ClF₃) is 0.520 M/s, what is the rate of disappearance of F₂?
#### Given Reaction:
\[ \text{Cl}_2(g) + 3 \text{F}_2(g) \rightarrow 2 \text{ClF}_3(g) \]
#### Options:
- A. –1.56 M/s
- B. –0.0433 M/s
- C. –0.780 M/s
- D. –0.173 M/s
- E. –0.390 M/s
#### Explanation:
In this problem, we are asked to determine the rate at which fluorine gas (F₂) is consumed based on the given rate of formation of chlorine trifluoride (ClF₃).
To solve this, we use the stoichiometry of the given reaction. The stoichiometric coefficients indicate the following relationships:
- 2 moles of ClF₃ are formed per 3 moles of F₂ consumed.
Therefore, we can set up a relationship between the rates of formation and disappearance as follows:
\[ \frac{\Delta [\text{ClF}_3]}{\Delta t} \times \frac{3}{2} = -\frac{\Delta [\text{F}_2]}{\Delta t} \]
Given:
\[ \frac{\Delta [\text{ClF}_3]}{\Delta t} = 0.520 \text{ M/s} \]
Thus:
\[ 0.520 \text{ M/s} \times \frac{3}{2} = \frac{\Delta [\text{F}_2]}{\Delta t} \]
\[ 0.520 \times 1.5 = \frac{\Delta [\text{F}_2]}{\Delta t} \]
\[ \frac{\Delta [\text{F}_2]}{\Delta t} = 0.780 \text{ M/s} \]
Since the rate of disappearance is being asked for, which should be given as a negative rate of change:
\[ \frac{\Delta [\text{F}_2]}{\Delta t} = -0.780 \text{ M/s} \]
#### Correct Answer:
C. –0.780 M/s
This calculation confirms that the rate of disappearance of F₂
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