If the pH of a 0.0850 M solution of HB1O2 is 2.29, then what is the value for the acidity constant, Ka, of HBrO2? HB1O2(aq) + H20(I) H3O*(aq) + Br0, (aq) K¸ = ?
If the pH of a 0.0850 M solution of HB1O2 is 2.29, then what is the value for the acidity constant, Ka, of HBrO2? HB1O2(aq) + H20(I) H3O*(aq) + Br0, (aq) K¸ = ?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![**Problem Statement:**
If the pH of a 0.0850 M solution of HBrO₂ is 2.29, then what is the value for the acidity constant, Kₐ, of HBrO₂?
**Chemical Equation:**
\[ \text{HBrO}_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) \rightleftharpoons \text{H}_3\text{O}^+(\text{aq}) + \text{BrO}_2^−(\text{aq}) \]
\[ K_a = ? \]
**Calculation Pathway:**
To find the \( K_a \), use the equation for the equilibrium constant for acids:
\[ K_a = \frac{[\text{H}_3\text{O}^+][\text{BrO}_2^-]}{[\text{HBrO}_2]} \]
**Provided Values:**
- Initial concentration of HBrO₂: 0.0850 M
- pH: 2.29
**Steps for Calculation:**
1. **Calculate the Hydronium Ion Concentration (\([\text{H}_3\text{O}^+]\)):**
From the pH value:
\[ [\text{H}_3\text{O}^+] = 10^{-\text{pH}} = 10^{-2.29} \]
2. **Determine Changes in Concentrations:**
- Initial concentration of HBrO₂: 0.0850 M
- Change in concentration of HBrO₂ and formation of \(\text{H}_3\text{O}^+\) = \(x\)
3. **Expression for Kₐ:**
Substitute the concentrations into the equilibrium expression to solve for \( K_a \).
4. **Conclusion and Analysis:**
Complete the calculation and then answer the following:
*Given the information above, is the bromite ion, \(\text{BrO}_2^-\), a strong base, a weak base, or not basic in water?*
Use the result of the \( K_a \) value to determine the basicity of \(\text{BrO}_2^-\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F092bd7db-9bdb-4d81-a056-eb65c4616336%2F684b6020-db09-4a66-b1a8-46d1d4ed3bb7%2Fhl5jzd_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
If the pH of a 0.0850 M solution of HBrO₂ is 2.29, then what is the value for the acidity constant, Kₐ, of HBrO₂?
**Chemical Equation:**
\[ \text{HBrO}_2(\text{aq}) + \text{H}_2\text{O}(\text{l}) \rightleftharpoons \text{H}_3\text{O}^+(\text{aq}) + \text{BrO}_2^−(\text{aq}) \]
\[ K_a = ? \]
**Calculation Pathway:**
To find the \( K_a \), use the equation for the equilibrium constant for acids:
\[ K_a = \frac{[\text{H}_3\text{O}^+][\text{BrO}_2^-]}{[\text{HBrO}_2]} \]
**Provided Values:**
- Initial concentration of HBrO₂: 0.0850 M
- pH: 2.29
**Steps for Calculation:**
1. **Calculate the Hydronium Ion Concentration (\([\text{H}_3\text{O}^+]\)):**
From the pH value:
\[ [\text{H}_3\text{O}^+] = 10^{-\text{pH}} = 10^{-2.29} \]
2. **Determine Changes in Concentrations:**
- Initial concentration of HBrO₂: 0.0850 M
- Change in concentration of HBrO₂ and formation of \(\text{H}_3\text{O}^+\) = \(x\)
3. **Expression for Kₐ:**
Substitute the concentrations into the equilibrium expression to solve for \( K_a \).
4. **Conclusion and Analysis:**
Complete the calculation and then answer the following:
*Given the information above, is the bromite ion, \(\text{BrO}_2^-\), a strong base, a weak base, or not basic in water?*
Use the result of the \( K_a \) value to determine the basicity of \(\text{BrO}_2^-\).
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