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If the person in the example is a Terminator machine that is composed of 99.99% Aluminum. How much energy is required to raise his temperature on the said problem?

If the person in the example is a Terminator machine that is composed of 99.99% Aluminum. How much energy is required to raise his temperature on the said problem?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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If the person in the example is a Terminator machine that is composed of 99.99% Aluminum. How much energy is required to raise his temperature on the said problem?

During a bout with the flu an 80 kg man ran a fever of 39.0°C (102.2°F) instead of the normal body temperature of 37.0°C (98.6°F). Assuming that the human body is mostly water, how much heat is required to raise his temperature by that amount? IDENTIFY and SET UP This problem uses the relationship among heat (the target variable), mass, specific heat, and tem- perature change. We use Eq. (17.13) to determine the required heat Q. with m = 80 kg, c = 4190 J/kg · K (for water), and AT = 39.0°C - 37.0°C = 2.0 C = 2.0 K. EXECUTE From Eq. (17.13), Q = mc AT = (80 kg)(4190 J/kg · K)(2.0 K) = 6.7 x 10° J
Transcribed Image Text:During a bout with the flu an 80 kg man ran a fever of 39.0°C (102.2°F) instead of the normal body temperature of 37.0°C (98.6°F). Assuming that the human body is mostly water, how much heat is required to raise his temperature by that amount? IDENTIFY and SET UP This problem uses the relationship among heat (the target variable), mass, specific heat, and tem- perature change. We use Eq. (17.13) to determine the required heat Q. with m = 80 kg, c = 4190 J/kg · K (for water), and AT = 39.0°C - 37.0°C = 2.0 C = 2.0 K. EXECUTE From Eq. (17.13), Q = mc AT = (80 kg)(4190 J/kg · K)(2.0 K) = 6.7 x 10° J
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