If the magnitude of F2 were increased by 1/3, what is the resultant moment at A? Round your numbers to the nearest whole number.
If the magnitude of F2 were increased by 1/3, what is the resultant moment at A? Round your numbers to the nearest whole number.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
If the magnitude of F2 were increased by 1/3, what is the resultant moment at A? Round your numbers to the nearest whole number.
Transcribed Image Text:During a gantry crane maneuver forces exerted on the frame
F₁ = = -720k lb
1
F2 = (-300i + 700j + 190k)lb
F3 = (450i 700j – 320k)lb
Determine the resultant moment of the three forces about the base of the crane at A.
F3
75 ft
Z
B
A
F2
10 ft
50 ft
FBD
F3 = (450i
-700j
-320k) lb
75 ft
Z
T2,3
F₂:
= (-300i + 700j + 190k) lb
B(0,0,75)
'10 ft
Figure 4. Gantry crane diagram and FBD.
F₁=(-720k) lb
50 ft
(0,0,0)A C(0,10,0)
MRA
y
![P1 =
¸ = (0 − 0)i + (10 − 0)j + (0 – 0)k = (10j) ft
* 2,3 = (0 - 0)i + (0 - 0)j + (75 −0)k = (75k) ft
MRA
=
• Σ(˜ × F) = (F1 × F1) + (F2 × F2) + (T3 × F3)
i
= 0
0
j
10
0
k
0 +
-720
j
k
i
j
k
0
75 +
0
0
75
-300 700 190 450 -700 -320
i
0
= [(−7, 200)i – Oj + 0k)] + [(0 − 52, 500)į – (0+ 22, 500)j + 0k)] +
[(0 + 52, 500)ż - (0 – 33, 750)j + Ok] ft — lb
MRA = (-7,200i + 11,250j) ft – lb](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F511d779c-bf10-4315-98b1-4f0038c55113%2F937c290f-c718-4af6-9bd4-6eabc4f9dd75%2Fr8kavlb_processed.png&w=3840&q=75)
Transcribed Image Text:P1 =
¸ = (0 − 0)i + (10 − 0)j + (0 – 0)k = (10j) ft
* 2,3 = (0 - 0)i + (0 - 0)j + (75 −0)k = (75k) ft
MRA
=
• Σ(˜ × F) = (F1 × F1) + (F2 × F2) + (T3 × F3)
i
= 0
0
j
10
0
k
0 +
-720
j
k
i
j
k
0
75 +
0
0
75
-300 700 190 450 -700 -320
i
0
= [(−7, 200)i – Oj + 0k)] + [(0 − 52, 500)į – (0+ 22, 500)j + 0k)] +
[(0 + 52, 500)ż - (0 – 33, 750)j + Ok] ft — lb
MRA = (-7,200i + 11,250j) ft – lb
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