If the insolation of the Sun shining on asphalt is 7.3 × 102 W/m2, what is the change in temperature of a 1.5 m2 by 5.0 cm thick layer of asphalt in 1.0 hr? (Assume the albedo of the asphalt is 0.12, the specific heat of asphalt is 0.22 cal/g · ° C, and the density of asphalt is 2.3 g/cm3.)
If the insolation of the Sun shining on asphalt is 7.3 × 102 W/m2, what is the change in temperature of a 1.5 m2 by 5.0 cm thick layer of asphalt in 1.0 hr? (Assume the albedo of the asphalt is 0.12, the specific heat of asphalt is 0.22 cal/g · ° C, and the density of asphalt is 2.3 g/cm3.)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
1.
If the insolation of the Sun shining on asphalt is
7.3
what is the change in temperature of a
×
102 W/m2,1.5 m2
by
5.0 cm
thick layer of asphalt in
1.0 hr?
(Assume the albedo of the asphalt is 0.12, the specific heat of asphalt is
0.22 cal/g
and the density of asphalt is
·
°
C,2.3 g/cm3.)
|
2. If the insolation of the Sun shining on seawater is
8.7
×
102 W/m2,what is the change in temperature of a
2.0 m2
by
19.0 cm
thick layer of seawater at the surface in
2.0 hr?
(Assume the albedo of the seawater is 0.4, the specific heat of seawater is
0.92 cal/g
·
°
C,and the density of seawater is
1.03 g/cm3.)
Δ
T =
3. If a
Dball =
cm
2.0 mm
thick piece of plastic sheeting is being placed around a ball to represent
50 percent
of the mass of Earth's atmosphere, what is the diameter of the ball needed to model Earth? Use
1.2756
for the Earth's diameter and
×
104 km5.6 km
for the thickness of
50 percent
of the mass of Earth's atmosphere. Express the answer in standard scientific notation.Dball =
×
10
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