If the initial partial pressure of HI is 0.171 atm, what is the equilibrium partial pressure for HI? 2 HI(g) H2₂(g) +12(g) Kp = 0.0063 at 500 K
If the initial partial pressure of HI is 0.171 atm, what is the equilibrium partial pressure for HI? 2 HI(g) H2₂(g) +12(g) Kp = 0.0063 at 500 K
Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter13: Fundamental Equilibrium Concepts
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Problem 12E: Show that the complete chemical equation, the total ionic equation, and the net ionic equation for...
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If the initial partial pressure of HI is 0.171 atm, what is the equilibrium partial pressure for HI?
2 HI(g)
H₂(g) + 12(g) Kp = 0.0063 at 500 K"
Transcribed Image Text:Question 5
If the initial partial pressure of HI is 0.171 atm, what is the equilibrium partial pressure for HI?
2 HI(g)
H₂(g) + 12(g) Kp = 0.0063 at 500 K
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