I understand for static equilibrium all the forces should sum up to zero but I'm just not understanding how I should have found these answers. 5:22 PM Sat Feb 2061%A openvellum.ecollege.comScoresPracticeCompleteeТextI Review I Constants I Periodic TableIn the Skycoaster amusement park ride, riders aresuspended from a tower by a long cable. A second cablethen lifts them until they reach the starting positionindicated in (Figure 1). The lifting cable is then released,and the riders swing down the circular arc shown.Study AreaPart ADocument SharingIf the four riders have a total mass of 190 kg,what is the tension in the left cable just beforeUser Settingsrelease?Course Tools>Express your answer with the appropriateunits.Tieft= 2600 NSubmitPrevious AnswersFigure1 of 1All attempts used; correct answerdisplayed15°26°Part BWhat is the tension in the right cable just beforerelease?Express your answer with the appropriateunits.Tright= 2700 NSubmitPrevious AnswersP PearsonCopyright © 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy |Permissions | Contact Us |

The mass of the riders is m=190 kg The weight of the riders is; W=mg=190×9.8=1862 N The following…

Answered: If the four riders have a total mass of…

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I understand for static equilibrium all the forces should sum up to zero but I'm just not understanding how I should have found these answers.

5:22 PM Sat Feb 20
61%
A openvellum.ecollege.com
Scores
Practice
Complete
eТext
I Review I Constants I Periodic Table
In the Skycoaster amusement park ride, riders are
suspended from a tower by a long cable. A second cable
then lifts them until they reach the starting position
indicated in (Figure 1). The lifting cable is then released,
and the riders swing down the circular arc shown.
Study Area
Part A
Document Sharing
If the four riders have a total mass of 190 kg,
what is the tension in the left cable just before
User Settings
release?
Course Tools
>
Express your answer with the appropriate
units.
Tieft
= 2600 N
Submit
Previous Answers
Figure
1 of 1
All attempts used; correct answer
displayed
15°
26°
Part B
What is the tension in the right cable just before
release?
Express your answer with the appropriate
units.
Tright
= 2700 N
Submit
Previous Answers
P Pearson
Copyright © 2021 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy |
Permissions | Contact Us |

Expert Solution

Part B (Step 1)

The mass of the riders is m=190 kg

The weight of the riders is;

$\begin{array}{rcl} W & = & m g \\ = & 190 \times 9.8 \\ = & 1862 N \end{array}$

The following is the free-body diagram:

Balancing the force along x-direction;

$\begin{array}{rcl} T_{1} \cos 15 & = & T_{2} \cos 26 \\ T_{1} & = & 0.93 T_{2} \end{array}$

Balancing the force along y-direction;

$\begin{array}{rcl} W & = & T_{1} \sin 15 + T_{2} \sin 26 \\ W & = & 0.93 T_{2} \sin 15 + T_{2} \sin 26 \\ 1862 & = & 0.68 T_{2} \\ T_{2} & \approx & 2738 N \end{array}$

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