If the exact volume of rignt circular Cylinder is 200 r cm3 and it's altidude measures 8cm, what is the measure Of the radius of the circular base?

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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**Volume Calculation of a Right Circular Cylinder**

*Exercise 9:*

If the exact volume of a right circular cylinder is \(200\pi \, \text{cm}^3 \) and its altitude measures 8 cm, what is the measure of the radius of the circular base?

---

To solve this, we can use the formula for the volume of a right circular cylinder:

\[ V = \pi r^2 h \]

Where:
- \( V \) is the volume
- \( r \) is the radius of the base
- \( h \) is the height (altitude)

Given:
- \( V = 200\pi \, \text{cm}^3 \)
- \( h = 8 \, \text{cm} \)

We need to find the radius \( r \). 

Let's substitute the known values into the volume formula and solve for \( r \):

\[ 200\pi = \pi r^2 \cdot 8 \]

Simplify by dividing both sides by \( \pi \):

\[ 200 = r^2 \cdot 8 \]

Then divide both sides by 8:

\[ 25 = r^2 \]

Finally, take the square root of both sides:

\[ r = \sqrt{25} \]

\[ r = 5 \, \text{cm} \]

Thus, the radius of the circular base is 5 cm.
Transcribed Image Text:**Volume Calculation of a Right Circular Cylinder** *Exercise 9:* If the exact volume of a right circular cylinder is \(200\pi \, \text{cm}^3 \) and its altitude measures 8 cm, what is the measure of the radius of the circular base? --- To solve this, we can use the formula for the volume of a right circular cylinder: \[ V = \pi r^2 h \] Where: - \( V \) is the volume - \( r \) is the radius of the base - \( h \) is the height (altitude) Given: - \( V = 200\pi \, \text{cm}^3 \) - \( h = 8 \, \text{cm} \) We need to find the radius \( r \). Let's substitute the known values into the volume formula and solve for \( r \): \[ 200\pi = \pi r^2 \cdot 8 \] Simplify by dividing both sides by \( \pi \): \[ 200 = r^2 \cdot 8 \] Then divide both sides by 8: \[ 25 = r^2 \] Finally, take the square root of both sides: \[ r = \sqrt{25} \] \[ r = 5 \, \text{cm} \] Thus, the radius of the circular base is 5 cm.
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