Answered: If the circles…

If the circles x\power{2}+y\power{2}+2a'x+2b'y+c'=0 and 2x\power{2}+2y\power{2}+2ax+2ay+c=0 intersect orthogonally,then prove that aa'+bb'=c+\frac{c'|2}.

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.7: Distinguishable Permutations And Combinations

Problem 21E

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Question

If the circles x\power{2}+y\power{2}+2a'x+2b'y+c'=0 and 2x\power{2}+2y\power{2}+2ax+2ay+c=0 intersect orthogonally,then prove that aa'+bb'=c+\frac{c'|2}.

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