If the circle with equation (x – a)? + (y – b)? = 36 has its centre on the y-axis and passes through the point with coordinates (6, 6), then: A a = 0 and b = 6 В a = 0 and b=-6 a = 2 and b = 0- %3D D a =-6 and b =0 E a = 6 and b = 0-

Q: Write the standard form of the equation of the circle given x2 - 6x + y2 + 8y + 12 = 36

A: To rewrite the given equation to the standard equation of the circle (x-a)^2+(y-b)^2 =r^2, center…

Q: Find the equation of the smaller circle that touches the circles x2 +y2=1  and passes through the…

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Q: Write the standard form of the equation of the circle with the given center and radius. (10, 0); 2

A: Given center (h,k)=(10, 0)  radius, r= 2

Q: Write the equation of the circle with center at   (4, 3) and touching the line 3x + y = –15.

A: Given that, the circle with center at 4,3 and touching the line 3x+y=-15.   The objective is to…

Q: Find the equation of the circle that Passes through the points A(2/ 3) B(-4/ 3) and c(3/2)

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Q: Find the standard form of the equation of the circle with a diameter having two points (1, -6) & (7,…

A: The end points of diameter of the circle are (1,-6)  and (7,2). The standard form of equation of…

Q: Find the equation of a circle whose center is at (5, -1) and radius 3.

A: Equation of a circle is given by : ( x - h )2 + ( y - k )2 = r2  Where (h,k) is the centre of the…

Q: menE C. Find the center and the radius of the following equation: 5. x + y -16x+8y+31=0 6. x* +y…

A: Given equation of circle now we have to find centre and radius of circle as shown below

Q: Graph the equation x2/4+ y2/9 = 1, and give the centerand the endpoints of the major axis

A: Given equation x24+y29=1

Q: Determine the center and radius of a circle whose equation is x² + y² + 8x - 6y - 24 = 0.

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Q: 4. Which equation represents a circle with center (9,-8) and a radius of 5 units? A (x-9)²+(v + 8)²…

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Q: Find the equation of the circle circumscribed by the triangle ABC, where A=[-1,-1], B=[-5,2],…

A: Triangle ABC with vertices A-1, -1, B-5, 2 & C1, 10. Now let Ph, k be the center of the circle.…