If the accelerating plates are 0.960 cm apart, and have a potential difference of 2.50x104 V, what is the magnitude of the uniform electric field between them? E = V/m Submit Request Answer
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![If the accelerating plates are 0.960 cm apart, and have a potential difference of 2.50x10 V, what is the magnitude of the
uniform electric field between them?
E=
V/m
Submit
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- Show that the force on each plate of a parallel plate capacitor has a magnitude equal to (½) QE, where Q is the charge on the capacitor, and E is the magnitude of electric field between the plates. Explain the origin of the factor ½.A charged ring with charge Q = 644 nC and radius R=0.67 m is placed in a tank of water. What is the electric field at the point z = 0.085 m above the midpoint of the ring, if the dielectric constant of water is 80.4? Answer in N/C and round your answer to have one digit after the decimal. Water 20 °C K = 80.4 Your Answer: AnswerWhat is the potential difference between xi = 10 cm and xf = 40 cm in the uniform electric field Ex = 2000 V/m?
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- Please asapA dipole with –Q at the origin (0,0) and the +Q at coordinates x= 4.00 cm, y = 3.00 cm is in an Electric field, E = 4.25 V/m directed to the right, +x . (Q = 0.400 C) Draw and label a figure.A parallel plate capacitor has a surface charge density of magnitude o = 0.00433 C/m² on each plate. A small sphere, charged to Q = 9.40 × 10-6 C and located between the plates, undergoes a displacement of magnitude d = 0.143 m. Refer to the figure, which is not drawn to scale. y +++++++ Using the symbols in the palette, not their numeric equivalents, enter an expression, in Cartesian unit-vector notation, for the electric field within the capacitor. If the displacement is from left to right, then how much work, in joules, is performed on the sphere by the electric field? At what speed, in meters per second, is the sphere moving when it completes the displacement if it starts from rest and its mass is 0.115 kg? X