If tan(0) and sin(0) > 0, then sin(0) = cos(6) sec(0) = csc(0) = %3D cot (0) =

Q: Q4// Find the value of csc(sec-1 2) + cos(tan=²(-V3)).

A: Here  given as Use some trigonometric formula as

Q: Graph off (x) = cos2 x - 2 sin x/4.

A:

Q: 4 sec(8) = find cot(0) 2

A: Use trigonometric rations

Q: Verify that (sin(0) csc(0))+ (cot(0) tan(0)) = 2

A: We have to verify,

Q: sin(2w)dw =

A:

Q: if sin (-x) = -0.97, find cos ((pi/2)-x) if tan (-x) = -2.36, find cot (x - (pi/2)) if sec (x -…

A:

Q: Show that Cosx dx 9- Sin 3D

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Q: dy If y = tan-[ sec2(5x² + 1) csc-3 (cos 3x)]. Find

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Q: Find sec(x) and csc(x) if tan(x) =7 and sin(x) >0

A: The objective is to find sec(x) and csc(x) if tan(x) =7 and sin(x) >0

Q: Si cos°(3x)sin (3x) – cos (3x) sin°(3x) dx

A: First we common out cos7(3x) sin7(3x) and then apply the formula cos2(3x)-sin2(3x)=cos(6x)

Q: Find sec(?) if tan(?) = 21/20 and cos(?)>0. sec(?) =

A: