If tan x = -1/3, cos x > 0, then sin 2x = cos2x = tan 2x

Q: ·S Evaluate cos x sin³ x dx. + C

A: To evaluate the following integral.

Q: If z² - 3yz² + xyz -2=0, find Az дz and дх ду

A: The objective is to find the Partial derivatives.

Q: simplify sin x-1/cos x - cos x /sin x-1

A: The given expression is

Q: Verify the identity: (cos 4x - cos 2x)/(sin 2x - sin 4x) = tan 3x

A:

Q: If tan x = 3, cos x > 0, , then - sin 2x cos 2x tan 2x %3D

A:

Q: Show that os (2 tan~ r) COs

A: We have to prove that cos(2tan-1x)=1-x21+x2.

Q: Is Cscx-1/1-Sinx=cscx

A:

Q: Sinx=2/3 Cosx=? Tanx=?

A: Question is solved.

Q: If cos x = 4/5, csc x < 0, then sin 2x cos2x = tan 2x

A: Cosx=4/5 ,cscx&lt;0

Q: Find sec2x if sin x = 6/10 and sec x < 0

A:

Q: tan x= -4 and sin x is negative

A: Here tanx=-4we know trigonometric identity,sec2x=1+tan2xsec x=±1+tan2xsec x=±1+(-4)2sec…

Q: Verify identity cos2 x - sin2 x = 1 - 2 sin2 x.

A: The given trigonometric equation (identity) is: cos2x-sin2x=1-2sin2 x To verify this, take the left…

Q: cosx+1=sinx

A: