If sec(0) = = 10,0 <0s

Q: Evaluate the following leaving the result as an EXACT value. cos⁡(tan^-1⁡(4/3)+sin^−1⁡(−2/5))

A: We have to solve the problem

Q: Sinx=1/2 Cos2x=

A:

Q: Differentiate y = (-6+sinx)/(x+cosx)

A:

Q: Scos x vsin x dx (sin x)i-(sinx) +C (sin x)i +(sinx)+c c. (sinx)- (sinx) + C (sinx)i +(sinx)+c A. B.…

A: ∫cos3xsinxdx

Q: Graph off (x) = cos2 x - 2 sin x/4.

A:

Q: If sinx^2 =a/b find cos(90-x)

A: See the details solution in below I am consider  sin(x^2 )

Q: 2 cos "(\) tan-

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Q: if Sec X = 2 then tanx +Cos X =

A:

Q: Show that os (2 tan~ r) COs

A: We have to prove that cos(2tan-1x)=1-x21+x2.

Q: (sin A)^4-(cos A)^4

A:

Q: find solution set of tan-1x-cot-1x=cos-1(2-x)

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Q: *cosx= 24 sinxyo, cos (x+5") 25

A: Given: cosα=2425, sinα&gt;0 To determine: cosα+5π6

Q: Find cos(sin^−1(−1/2))

A: Trigonometric

Q: Cos (-x)= - Cosx

A: Let, cos-1(-x)=yThen,-x=cosyx=-cosy

Q: Find the exact Value of -1 Cos (tan'a + Sin ¹ 1/27) 13

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Q: cos x-sinxtanx=

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Q: Show that sin²(x) cos(x) = sec(x) – cos(x)

A: We need to show the following. So,         Manipulating right side=secx-cosx=1-cos2xcosx=sin2xcosx

Q: cos(sin (0.1612)) -0.0131 O 0.9869 O 2.9869 O -1.0131 O 1.9869

A: sin^-1(0.1612)=0.1619064343923739 cos(0.1619064343923739)=0.98692175981 that is equal to =0.9869

Q: (sec(x) + 1)/(tan x) = (sin x)/(1 - cos x)

A:

Q: If tan A = sqrt (2) - 1  Find tha value of sinA cos A =( sqrt(2) )/(4))

A: