If r₂ and r₂ are the values of r that you found in part (a), show that every member of the family of functions y = ae1* + be 2* is also a solution. Step 1 We must decide whether 4f"(x) + 2f'(x) - 2f(x) = 0 for f(x) = aex/2 + bex. We have f'(x) = માંજ - be -X act act - be Step 2 Substituting and combining like terms, we get 4f"(x) + 2f'(x) - 2f(x) = Submit Skip (you cannot come back) ex/2 and f"(x) = -ae + || H X + be-x act +1 + bez

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A: