If P(E) = 0.2, P(F) = 0.3, and E and F are independent events, find P(E and F). 1) 0.06 2) 0.08 3) 0.1 4) 0.12

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.3: Using Data Displays
Problem 2C
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**Problem Statement:**

Given:
- \( P(E) = 0.2 \)
- \( P(F) = 0.3 \)
- E and F are independent events

Find \( P(E \text{ and } F) \).

**Options:**

1. \( 0.06 \)
2. \( 0.08 \)
3. \( 0.1 \)
4. \( 0.12 \)
5. \( 0.5 \)
6. \( 0.9 \)
7. \( 0 \)
8. \( 1 \)

**Solution:**

To find the probability of both events E and F occurring, denoted \( P(E \text{ and } F) \), we use the fact that the events are independent. For independent events, the probability of both occurring is the product of their individual probabilities:

\[
P(E \text{ and } F) = P(E) \times P(F)
\]

Given:
\[
P(E) = 0.2 \quad \text{and} \quad P(F) = 0.3
\]

Therefore:
\[
P(E \text{ and } F) = 0.2 \times 0.3 = 0.06
\]

**Answer:**

The correct option is:

1. \( 0.06 \)
Transcribed Image Text:**Problem Statement:** Given: - \( P(E) = 0.2 \) - \( P(F) = 0.3 \) - E and F are independent events Find \( P(E \text{ and } F) \). **Options:** 1. \( 0.06 \) 2. \( 0.08 \) 3. \( 0.1 \) 4. \( 0.12 \) 5. \( 0.5 \) 6. \( 0.9 \) 7. \( 0 \) 8. \( 1 \) **Solution:** To find the probability of both events E and F occurring, denoted \( P(E \text{ and } F) \), we use the fact that the events are independent. For independent events, the probability of both occurring is the product of their individual probabilities: \[ P(E \text{ and } F) = P(E) \times P(F) \] Given: \[ P(E) = 0.2 \quad \text{and} \quad P(F) = 0.3 \] Therefore: \[ P(E \text{ and } F) = 0.2 \times 0.3 = 0.06 \] **Answer:** The correct option is: 1. \( 0.06 \)
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