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If P(B | A) > P(B), show that P(B' | A) < P(B'). [Hint: Add P(B' | A) to both sides of the given inequality and then use the fact that P(A | B) + P(A' | B) = 1.] P(B | A) + P(B' | A) > P(B) + P(B' | A) > P(B) + P(B' | A) > P(B' | A) V > P(B' | A) P(B' | A) < P(B') 1 - P(B) P(B')

If P(B | A) > P(B), show that P(B' | A) < P(B'). [Hint: Add P(B' | A) to both sides of the given inequality and then use the fact that P(A | B) + P(A' | B) = 1.] P(B | A) + P(B' | A) > P(B) + P(B' | A) > P(B) + P(B' | A) > P(B' | A) V > P(B' | A) P(B' | A) < P(B') 1 - P(B) P(B')

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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If P(B | A) > P(B), show that P(B' | A) < P(B'). [Hint: Add P(B' | A) to both sides of the given inequality and then use the fact that P(A | B) + P(A' | B) = 1.] P(B | A) + P(B' | A) > P(B) + P(B' | A) > P(B) + P(B' | A) > P(B' | A) > P(B' | A) P(B' | A) < P(B') 1 - Р(В) P(B')
Transcribed Image Text:If P(B | A) > P(B), show that P(B' | A) < P(B'). [Hint: Add P(B' | A) to both sides of the given inequality and then use the fact that P(A | B) + P(A' | B) = 1.] P(B | A) + P(B' | A) > P(B) + P(B' | A) > P(B) + P(B' | A) > P(B' | A) > P(B' | A) P(B' | A) < P(B') 1 - Р(В) P(B')
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