If ON=7x-5, LM = 6x + 3, NM =x-4, and OL = 2y + 5, ind the values of x and y given that LMNO is a parallelogram.

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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**Mathematics Problem: Determining Values in a Parallelogram**

**Problem Statement:**

If \(ON = 7x - 5\), \(LM = 6x + 3\), \(NM = x - 4\), and \(OL = 2y + 5\), find the values of \(x\) and \(y\) given that \(LMNO\) is a parallelogram.

**Solution Approach:**

A parallelogram is a quadrilateral with opposite sides that are equal and parallel. Therefore, in \(LMNO\):

1. \(ON = LM\)
2. \(NM = OL\)

Using the given equations:

1. For the sides \(ON\) and \(LM\):
   \[
   ON = 7x - 5
   \]
   \[
   LM = 6x + 3
   \]
   Since \(ON = LM\):
   \[
   7x - 5 = 6x + 3
   \]
   Simplifying this equation to solve for \(x\):
   \[
   7x - 6x = 3 + 5
   \]
   \[
   x = 8
   \]

2. For the sides \(NM\) and \(OL\):
   \[
   NM = x - 4
   \]
   \[
   OL = 2y + 5
   \]
   Substituting \(x = 8\) in \(NM\):
   \[
   NM = 8 - 4 = 4
   \]
   Since \(NM = OL\):
   \[
   4 = 2y + 5
   \]
   Solving for \(y\):
   \[
   4 - 5 = 2y
   \]
   \[
   -1 = 2y
   \]
   \[
   y = -\frac{1}{2}
   \]

**Solution:**

Thus, the values of \(x\) and \(y\) are:
\[
x = 8
\]
\[
y = -\frac{1}{2}
\]
Transcribed Image Text:**Mathematics Problem: Determining Values in a Parallelogram** **Problem Statement:** If \(ON = 7x - 5\), \(LM = 6x + 3\), \(NM = x - 4\), and \(OL = 2y + 5\), find the values of \(x\) and \(y\) given that \(LMNO\) is a parallelogram. **Solution Approach:** A parallelogram is a quadrilateral with opposite sides that are equal and parallel. Therefore, in \(LMNO\): 1. \(ON = LM\) 2. \(NM = OL\) Using the given equations: 1. For the sides \(ON\) and \(LM\): \[ ON = 7x - 5 \] \[ LM = 6x + 3 \] Since \(ON = LM\): \[ 7x - 5 = 6x + 3 \] Simplifying this equation to solve for \(x\): \[ 7x - 6x = 3 + 5 \] \[ x = 8 \] 2. For the sides \(NM\) and \(OL\): \[ NM = x - 4 \] \[ OL = 2y + 5 \] Substituting \(x = 8\) in \(NM\): \[ NM = 8 - 4 = 4 \] Since \(NM = OL\): \[ 4 = 2y + 5 \] Solving for \(y\): \[ 4 - 5 = 2y \] \[ -1 = 2y \] \[ y = -\frac{1}{2} \] **Solution:** Thus, the values of \(x\) and \(y\) are: \[ x = 8 \] \[ y = -\frac{1}{2} \]
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