If num.length=4 and num[i].length=2, What will be the values in the num array based on the code fragment given below? for(i=0;i
If num.length=4 and num[i].length=2, What will be the values in the num array based on the code fragment given below? for(i=0;i
Chapter8: Arrays
Section: Chapter Questions
Problem 9PE
Related questions
Question
![The educational content discusses a code fragment for initializing values in a two-dimensional array named `num`. Given parameters are `num.length=4` and `num[i].length=2`. The code snippet provided is:
```cpp
for(i=0; i<num.length; ++i) {
for(j=0; j<num[i].length; ++j) {
num[i][j] = i + j;
}
}
```
**Explanation of the Code:**
1. **Outer Loop (`for(i=0; i<num.length; ++i)`)**:
- Iterates over the first dimension of the array, `num`, from 0 to 3 (total 4 iterations).
2. **Inner Loop (`for(j=0; j<num[i].length; ++j)`)**:
- Iterates over the second dimension of the array for each `i`, from 0 to 1 (total 2 iterations).
3. **Assignment (`num[i][j] = i + j`)**:
- Sets each element of the 2D array `num` at position `[i][j]` to the sum of indices `i` and `j`.
**Final Values in `num` Array:**
- `i = 0`: `num[0][0] = 0 + 0 = 0`, `num[0][1] = 0 + 1 = 1`
- `i = 1`: `num[1][0] = 1 + 0 = 1`, `num[1][1] = 1 + 1 = 2`
- `i = 2`: `num[2][0] = 2 + 0 = 2`, `num[2][1] = 2 + 1 = 3`
- `i = 3`: `num[3][0] = 3 + 0 = 3`, `num[3][1] = 3 + 1 = 4`
**Resulting Array:**
```
num = [
[0, 1],
[1, 2],
[2, 3],
[3, 4]
]
```
This two-dimensional array is effectively populated using the loop structures and the formula `i + j`, demonstrating how nested loops can be used to fill arrays based on index calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1db393ef-43cb-43c9-b137-6acaeee410b9%2Fb8158924-789d-4ec2-b607-aedef67e1fbb%2F0y3f2e7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The educational content discusses a code fragment for initializing values in a two-dimensional array named `num`. Given parameters are `num.length=4` and `num[i].length=2`. The code snippet provided is:
```cpp
for(i=0; i<num.length; ++i) {
for(j=0; j<num[i].length; ++j) {
num[i][j] = i + j;
}
}
```
**Explanation of the Code:**
1. **Outer Loop (`for(i=0; i<num.length; ++i)`)**:
- Iterates over the first dimension of the array, `num`, from 0 to 3 (total 4 iterations).
2. **Inner Loop (`for(j=0; j<num[i].length; ++j)`)**:
- Iterates over the second dimension of the array for each `i`, from 0 to 1 (total 2 iterations).
3. **Assignment (`num[i][j] = i + j`)**:
- Sets each element of the 2D array `num` at position `[i][j]` to the sum of indices `i` and `j`.
**Final Values in `num` Array:**
- `i = 0`: `num[0][0] = 0 + 0 = 0`, `num[0][1] = 0 + 1 = 1`
- `i = 1`: `num[1][0] = 1 + 0 = 1`, `num[1][1] = 1 + 1 = 2`
- `i = 2`: `num[2][0] = 2 + 0 = 2`, `num[2][1] = 2 + 1 = 3`
- `i = 3`: `num[3][0] = 3 + 0 = 3`, `num[3][1] = 3 + 1 = 4`
**Resulting Array:**
```
num = [
[0, 1],
[1, 2],
[2, 3],
[3, 4]
]
```
This two-dimensional array is effectively populated using the loop structures and the formula `i + j`, demonstrating how nested loops can be used to fill arrays based on index calculations.
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