If num.length=4 and num[i].length=2, What will be the values in the num array based on the code fragment given below? for(i=0;i

EBK JAVA PROGRAMMING
9th Edition
ISBN:9781337671385
Author:FARRELL
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Chapter8: Arrays
Section: Chapter Questions
Problem 9PE
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The educational content discusses a code fragment for initializing values in a two-dimensional array named `num`. Given parameters are `num.length=4` and `num[i].length=2`. The code snippet provided is:

```cpp
for(i=0; i<num.length; ++i) {
    for(j=0; j<num[i].length; ++j) {
        num[i][j] = i + j;
    }
}
```

**Explanation of the Code:**

1. **Outer Loop (`for(i=0; i<num.length; ++i)`)**:
   - Iterates over the first dimension of the array, `num`, from 0 to 3 (total 4 iterations).

2. **Inner Loop (`for(j=0; j<num[i].length; ++j)`)**:
   - Iterates over the second dimension of the array for each `i`, from 0 to 1 (total 2 iterations).

3. **Assignment (`num[i][j] = i + j`)**:
   - Sets each element of the 2D array `num` at position `[i][j]` to the sum of indices `i` and `j`.

**Final Values in `num` Array:**

- `i = 0`: `num[0][0] = 0 + 0 = 0`, `num[0][1] = 0 + 1 = 1`
- `i = 1`: `num[1][0] = 1 + 0 = 1`, `num[1][1] = 1 + 1 = 2`
- `i = 2`: `num[2][0] = 2 + 0 = 2`, `num[2][1] = 2 + 1 = 3`
- `i = 3`: `num[3][0] = 3 + 0 = 3`, `num[3][1] = 3 + 1 = 4`

**Resulting Array:**

```
num = [
  [0, 1],
  [1, 2],
  [2, 3],
  [3, 4]
]
```

This two-dimensional array is effectively populated using the loop structures and the formula `i + j`, demonstrating how nested loops can be used to fill arrays based on index calculations.
Transcribed Image Text:The educational content discusses a code fragment for initializing values in a two-dimensional array named `num`. Given parameters are `num.length=4` and `num[i].length=2`. The code snippet provided is: ```cpp for(i=0; i<num.length; ++i) { for(j=0; j<num[i].length; ++j) { num[i][j] = i + j; } } ``` **Explanation of the Code:** 1. **Outer Loop (`for(i=0; i<num.length; ++i)`)**: - Iterates over the first dimension of the array, `num`, from 0 to 3 (total 4 iterations). 2. **Inner Loop (`for(j=0; j<num[i].length; ++j)`)**: - Iterates over the second dimension of the array for each `i`, from 0 to 1 (total 2 iterations). 3. **Assignment (`num[i][j] = i + j`)**: - Sets each element of the 2D array `num` at position `[i][j]` to the sum of indices `i` and `j`. **Final Values in `num` Array:** - `i = 0`: `num[0][0] = 0 + 0 = 0`, `num[0][1] = 0 + 1 = 1` - `i = 1`: `num[1][0] = 1 + 0 = 1`, `num[1][1] = 1 + 1 = 2` - `i = 2`: `num[2][0] = 2 + 0 = 2`, `num[2][1] = 2 + 1 = 3` - `i = 3`: `num[3][0] = 3 + 0 = 3`, `num[3][1] = 3 + 1 = 4` **Resulting Array:** ``` num = [ [0, 1], [1, 2], [2, 3], [3, 4] ] ``` This two-dimensional array is effectively populated using the loop structures and the formula `i + j`, demonstrating how nested loops can be used to fill arrays based on index calculations.
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