if n< d T(n)= - laT(n/b)+ f(n) if n2 d 1. if f(n) is O(n" 2. if f(n) is O(n™*“ log* n), then T(n) is O(n*.“ log**" n)| 3. if f(n) is 2(n*. *“), then T(n) is O(f (n)), provided af(n/b) S F (n) for some & <1. log, a-e ), then T(n) is O(no") log, a+e Which of the three cases above applies to an algorithm, the running time of which is described using the following recurrence relation: T(n) = 3 T(n/3) + n^/a Type 1 for case 1, and so on. For case 2, also specify a k value after a space, e.g., "2 2" Type N/A if the Master theorem is not applicable to the recurrence relation Answer:

if n< d T(n)= - laT(n/b)+ f(n) if n2 d 1. if f(n) is O(n" 2. if f(n) is O(n™“ log n), then T(n) is O(n*.“ log**" n)| 3. if f(n) is 2(n. “), then T(n) is O(f (n)), provided af(n/b) S F (n) for some & <1. log, a-e ), then T(n) is O(no") log, a+e Which of the three cases above applies to an algorithm, the running time of which is described using the following recurrence relation: T(n) = 3 T(n/3) + n^/a Type 1 for case 1, and so on. For case 2, also specify a k value after a space, e.g., "2 2" Type N/A if the Master theorem is not applicable to the recurrence relation Answer:

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def hailstone(n): h.append(int(n)) if n == 1: return h while n != 1: if n % 2 == 0: return hailstone(int(n/2)) else: return hailstone(int(3*n + 1))y=int(input("N: "))if y <= 0: print("N must be positive!")else: print("Hailstone sequences for 1 to " + str(y) + ":") m=0; i=1 for x in range(1, y+1): n = i h = [] h = hailstone(n) print(h) s=len(h) if s > m: m=s flag=n i=i+1 print("First longest sequence found in n =", + flag ) If i don't one the output have the square braket? How can I fix this code? Can you pleasw help me?
def hailstone(n): h.append(int(n)) if n == 1: return h while n != 1: if n % 2 == 0: return hailstone(int(n/2)) else: return hailstone(int(3*n + 1))y=int(input("N: "))if y <= 0: print("N must be positive!")else: print("Hailstone sequences for 1 to " + str(y) + ": ") m=0; i=1 for x in range(1, y+1): n = i h = [] h = hailstone(n) print(*h) print(",") s=len(h) if s > m: m=s flag=n i=i+1 print("First longest sequence found in n =", + flag ) How can I fix this code if I want a comma between each number, not each line?