If n=380 and p (p-hat) =0.49, find the margin of error at a 99% confidence level Give your answer to three decimals
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- N1=94 X1=26 N2=78 X2=39 Confidence interval 99% ?The 82.9% confidence interval estimate for μμ was (25.81, 31.35). Find the point estimate and the margin of error (ME) from this interval estimate. Point estimate = ME=If n=190 and ˆpp^ (p-hat) = 0.95, construct a 99% confidence interval.Give your answers to three decimals.
- Congratulations, you just made a confidence interval! But wait, how did we decide on the width of the interval? The middle of the interval is the sample mean. We start there, and then the "wiggle room" we give on either side of that center is called the margin of error (MOE). There's a formula for margin of error: 0 MOE = 2* √T This formula consists of three values: o is the standard deviation, n is the sample size, and z is a multiplier that we choose based on the confidence level we need. Confidence levels are expressed as percentages, the most common are 90%, 95%, and 99%: * Confidence Z Level value 90% 1.645 95% 1.96 99% 2.576 Let's practice computing a margin of error. For our earlier example about houses, suppose the standard deviation was 14 years, and the sample size was 30. Use a confidence level of 95% and determine the margin of error: σ Remember, we'll use the formula MOE = 2* . First fill in the numbers for each part of the formula: √n = σ= n = Now put it all together,…Express the confidence interval 89.4 % + 4.4 % in interval form. Express the answer in decimal format (do not enter as percents). Question Help: DVideo Submit Question 吕0 888 F6 F7 F4 F5 F2 F3 * @ #3 24 8 2 3 R Y w/Tq14
- I have only 30 min. Please helpplease sir solve last the two partsConstruct a confidence interval for p, - P, at the given level of confidence. X1 = 34, n1 = 273, x2 = 32, n2 = 313, 90% confidence The researchers are % confident the difference between the two population proportions, p, - P2, is between and (Use ascending order. Type an integer or decimal rounded to three decimal places as needed.)
- Please solve for margin of error and sample proportionSOLVE STEP BY STEP IN DIGITAL FORMAT 4.- In the Pedagogy career, you want to carry out a survey, for this you are asked to calculate a sample, knowing that there are 700 students from 19 to 89. Semester. With a confidence level of 97% (2.17), with a margin of error of 3%. With a probability in favor of 50% and a probability against of 50%.If n=580 and p (p-hat) =0.83, find the margin of error at a 95% confidence level Give your answer to three decimals Submit Question Jumn to Answer