If n=31, x(x-bar)=32, and s-6, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.

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**Educational Website Transcription:**

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**Constructing an 80% Confidence Interval**

Given:

- Sample size (\( n \)) = 31
- Sample mean (\( \bar{x} \)) = 32
- Sample standard deviation (\( s \)) = 6

Task: Construct a confidence interval at an 80% confidence level. Assume the data comes from a normally distributed population.

**Instructions:** Provide your answers rounded to one decimal place.

\[ < \mu < \]

[Input fields for the confidence interval]

--- 

**Note:**
To solve this problem, you would typically use the formula for a confidence interval for a normally distributed population:

\[ \text{Confidence Interval} = \bar{x} \pm z \left( \frac{s}{\sqrt{n}} \right) \]

Where \( z \) is the z-score corresponding to the desired confidence level. A lookup table or statistical software can be used to find this value.
Transcribed Image Text:**Educational Website Transcription:** --- **Constructing an 80% Confidence Interval** Given: - Sample size (\( n \)) = 31 - Sample mean (\( \bar{x} \)) = 32 - Sample standard deviation (\( s \)) = 6 Task: Construct a confidence interval at an 80% confidence level. Assume the data comes from a normally distributed population. **Instructions:** Provide your answers rounded to one decimal place. \[ < \mu < \] [Input fields for the confidence interval] --- **Note:** To solve this problem, you would typically use the formula for a confidence interval for a normally distributed population: \[ \text{Confidence Interval} = \bar{x} \pm z \left( \frac{s}{\sqrt{n}} \right) \] Where \( z \) is the z-score corresponding to the desired confidence level. A lookup table or statistical software can be used to find this value.
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